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vladimir2022 [97]
4 years ago
7

What is The strength of a hurricane is ranked from 1 to 5 on the _________________.

Chemistry
1 answer:
UkoKoshka [18]4 years ago
8 0
Richter Scale.

Hope this helps!
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Atoms of two different elements must have different
kogti [31]

Answer:

C atomic number

Explanation:

As u go from left to right the atomic number changes

So C is the answer,

I took the test on edge and that was the answer

3 0
3 years ago
State the difference that may be observed between the solids obtain by evaporating a solution of a solid to dryness or letting i
tresset_1 [31]

Answer:

It well melt.While theother one will dry

Explanation:

3 0
3 years ago
Which of the following conclusions can be drawn from JJ Thomson's cathode ray experiments?A.) Atoms contain electronsB.) Practic
kari74 [83]

Answer:

A.) Atoms contain electrons

Explanation:

J.J. Thomson conducted an experiment in which he took a gas at low pressure in a discharge tube and applied high voltage current. When he did so, he noticed that there are some particles emitting from cathode going towards the anode. <u>Then he concluded that they are negatively charged particles and coined them electrons.</u>

<u>Hence, out of the options:- A.) Atoms contain electrons is correct.</u>

3 0
3 years ago
1.Which description is not a property of an acid?
wlad13 [49]

Answer:

1.slimy feel

2.corrosive

Explanation:

hey friend hope it's help you...

8 0
2 years ago
Quinine is an important type of molecule that is involved in photosynthesis. The transport of electrons mediated by quinone in c
Irina18 [472]

Answer:

The heat of combustion is -25 kJ/g = -2700 kJ/mol.

Explanation:

According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.

Qcomb + Qcal = 0

Qcomb = - Qcal

The heat absorbed by the calorimeter can be calculated with the following expression.

Qcal = C × ΔT

where,

C is the heat capacity of the calorimeter

ΔT is the change in temperature

Then,

Qcomb = - Qcal

Qcomb = - C × ΔT

Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ

Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:

\frac{-5.0kJ}{0.1964g} =-25kJ/g

The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

\frac{-25kJ}{g} .\frac{108g}{1mol} =-2700kJ/mol

6 0
3 years ago
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