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2 years ago

Which is the the largest decimal? .345, .33, .332, .35

Mathematics

1 answer:

AysviL [449]2 years ago

7 0

0.345 or .345

Step-by-step explanation:

because that is the highest decimal number because it has higher values, I mean "345" is greater than "33", "35", and "332".

the only way the smallest number would be the highest number is when it have a negative symbol to it e.g -0.1 is greater than -0.2 due to the fact that -0.1 is closer to 0,1,2,3,..... than -0.2 According to the number line.

All I'm trying to say is that, if it's not a negative number then the one with the highest value or number is actually the highest number EXCEPT if it Hans the negative symbol (-) to it, then it's the opposite meaning the "smallest number" would be the highest number.

Hope this helps buddy, Good luck ✅.

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3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
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I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

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