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2 years ago

This graph represents the average number of animals that are seen in a veterinarian's office during the day.

Mathematics

1 answer:

defon2 years ago

6 0

Answer:

A. 10 animals seen in 1 hour

C. 60 animals seen in 6 hours

i dont know B sorry

Step-by-step explanation:

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Which value is equivalent to 3/11? OA A. 0.27 O B. 0.27 OC C. 3.6 OD. 3.

Sladkaya [172]

Answer:

0.27 repeating.

Step-by-step explanation:

So to solve this we just have to use division.

1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.

11 goes into 30 2 times, so we have:

0.2

and 30-22=8

So we can add another 0 and make it 80.

Then 11 goes into 80 7 times. So we have:

0.27

and 80-77=3

So again, add the 0, we have 30.

11 goes into 30 2 times, so:

0.272

and 30-22=8

Add another 0 we get 80.

11 goes into 80 7 times.

So finally, we have:

0.2727.

This is a repeating decimal.

This can be shown as:

0.27

So this is your answer!

I was a bit confused with which one it was on your answer key, but knowing that it is 0.27 I am guessing you can chose!

Hope this helps!

4 0

2 years ago

If two fair dice are rolled, what’s the probability that the product of the

Oksanka [162]

Answer:

4/1. ( not so sure tho)

Step-by-step explanation:

=[(6/6)×(6/6)] + [(5/6)×(6/6)] + [(6/6)×(5/6)]

=(36/36) + (30/36) + (30/36)

=(taking LCM) 96/36

=4/1.

hope this helps

8 0

2 years ago

Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m

JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment .

A) Determine the test statistic

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5) / $\sqrt{0.5*0.5 / 200}$ = 2.12

b) determine the p-value

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 ) = 1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0

2 years ago

How would you know if these are a positive or a negative 0,1) and (-3,6).

Ipatiy [6.2K]

Negative has the little dash in front of it

Thank you hope this helps

7 0

2 years ago

Asap pls help me i will give 30 points

Basile [38]

$▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪$

The rational values are :

$- \dfrac {1}{16}$

and

The Irrational values are :

$\sqrt{3}$

and

$\sqrt{2}$

6 0

2 years ago

Read 2 more answers