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Burka [1]
3 years ago
6

Is how much did a tree grow in one year a statistical question

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0
No it probably is either mathematics or earth science
romanna [79]3 years ago
7 0
Nope. It actually deals with mathematics
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Svetlanka [38]
The slope of the LM curve is the coefficient of Y, k over h, or the income sensitivity of demand for real money over the interest sensitivity of demand for real money. This ratio is important for monetary policy.
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2 years ago
ANYONE PLEASE HELP ME IN MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS TOMORROW:(
vladimir1956 [14]

Answer:

.....................

10)=(-3)^2.x^4×2.y^2(5.x^2y^6)-7^2x^5×2y^4×2

=(9×5)x^8+2y^2+6-49x^10y^8

=45x^8+2y^2+6-49x^10y^8

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3 years ago
Please help!! I don’t get it
Marrrta [24]

Answer:

Each hotdog costs $1.65

Each juice drink costs $1.05

Step-by-step explanation:

Let's begin by letting x represent the number of hot dogs and y the number of juice drinks.

The Baxter family bought 6 hot dogs and 4 juices for $14.10.

6x + 4y = 14.10

The Farley family bought 3 hot dogs and 4 juices for $9.15.

3x + 4y = 9.15

Now, we subtract these equations.

6x + 4y = 14.10\\- (3x + 4y = 9.15)

Since y has reversed coefficients, it gets eliminated. Now solve for x.

6x+4y-3x-4y=14.1-9.15\\3x = 4.95\\\frac{3x}{3} = \frac{4.95}{3}

\frac{4.95}{3} = 1.65

x = 1.65

NOW, we find y by substituting x with 1.65 (in either equation).

We'll use the first equation.

6x + 4y = 14.10

6(1.65) + 4y = 14.10

9.9 + 4y = 14.10\\4y = 14.1 - 9.9\\4y = 4.2

\frac{4y}{4} = \frac{4.2}{4} \\y = 1.05

x = 1.65

y = 1.05

x represents hotdogs and y represents juice drinks.

Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.

<em> I hope this helps! :)</em>

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3 years ago
Hunter has 2
Masteriza [31]

Answer:

Hunter played 3 rounds

Step-by-step explanation:

4 0
3 years ago
Select the correct answer.<br> Simplify the following expression.
OlgaM077 [116]

Answer:

A. 1/49, or 0.02040

3 0
2 years ago
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