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vladimir1956 [14]
1 year ago
10

URGENT! if ABCD is dilated by a factor of 2, the coordinate of A' would be:

Mathematics
1 answer:
koban [17]1 year ago
4 0

After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

<h3>How to determine the coordinates of an image after applying a rigid transformation</h3>

First of all, dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied on <em>geometric</em> loci such that the <em>Euclidean</em> distance at every point of the construction is conserved. Vectorially speaking, the dilation is expressed by the following formula:

A'(x, y) = A(x, y) + k · [A(x, y) - O(x, y)]     (1)

Where:

  • A(x, y) - Original point
  • O(x, y) - Center of dilation
  • A'(x, y) - Resulting point
  • k - Dilation factor

If we know that A(x, y) = (-3, -1), k = 2 and O(x, y) = (0, 0), then the coordinates of A' are:

A'(x, y) = (-3, -1) + 2 · [(-3, -1) - (0, 0)]

A'(x, y) = (-3, -1) + (-6, -2)

A'(x, y) = (-9, -3)

After dilating the quadrilateral ABCD by a factor of 2 and with respect to the origin, the point A(x, y) = (-3, -1) is transformed into the point A'(x, y) = (-9, -3).

To learn more on dilations: brainly.com/question/13176891

#SPJ1

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