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Mandarinka [93]
3 years ago
15

How do similar right triangles lead to the definitions of the trigonometric ratios?

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0
The ratio of two sides of one right triangle is the same of the corresponding sides of any its similar triangles.

Call a, b, c the sides of a right triangle and A, B, C the sides of any of its similar triangles.

Then a/b  = A/B, which means that this ratio is a constant.

The same for a/c = A/C, and b/c = B/C.

Even, the same is true for the inverses: b/a = B/A; c/b = C/B, and d/a = C/A.

Then, you can define a function for every one of these ratios. Those functions are the trigonometric functions.


 
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sveta [45]
<span>1)
11x+5y=20
2x+5y=-25

multiply the second equation by - 1 and add the result with the first equation:

11x + 5y = 20
- 2x - 5y = 25
-------------------
9x = 45

=> x = 45 / 9

=> x = 5

Replace in </span><span>2x+5y=-25

=> 2(5) + 5y = - 25

5y = - 25 - 10

5y = - 35

y = - 35 / 5

y = - 7


2)

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3x-7y=63</span>

Add the two equations:

3x + 3x + 0 = - 21 + 63

6x = 42

=> x = 42 / 6

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Replace in <span>3x-7y=63

3(7) - 7y = 63

=> 7y = 21 - 63

=-> 7y = - 42

=> y = - 42 / 6

=> y = - 7</span>
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Step-by-step explanation:

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