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likoan [24]
2 years ago
10

A train travels at 100 milers per hour. An equation can be written that compares the time (t) with the distance (d). Define the

domain and range​
Mathematics
1 answer:
Alenkasestr [34]2 years ago
8 0

Answer:

The domain is t ≥ 0

The range is D ≥ 0

Step-by-step explanation:

rate = \frac{distance}{time}

D(t) = 100t + d₀

t is the time measured in hours.

d₀ is the initial position of the train.

We can assume the distance they go is not negative so...

The domain is t ≥ 0

The range is D ≥ 0

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PLEASE HELP!!! Trapezoid ABCD was dilated to create trapezoid A'B'C'D'. Which statements are true about the trapezoids? Check al
hichkok12 [17]

Answer:

Option A , B and D are true.

The statement which are true:

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

Step-by-step explanation:

Given in figure trapezoid ABCD;

The coordinates of ABCD are:

A= (-4, 0)

B = (-2, 4)

C = (2,4)

D = (4, 0)

Since, trapezoid ABCD was dilated to create trapezoid A'B'C'D' as shown in figure;

The coordinates of A'B'C'D' are;

A' =(-2, 0)

B'=(-1, 2)

C' = (1, 2)

D' = (2, 0)

First calculate the length of AD

Using Distance formula for any two points i.e,

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since, A = (-4, 0) and D = (4, 0)

then;

Length of AD =  \sqrt{(4-(-4))^2+(0-0)^2}  = \sqrt{(4+4)^2} =\sqrt{64}=8 units

Therefore, the length of side AD is, 8 units.

Similarly find the length of A'D'.

Where A' = (-2, 0) and D' =(2,0)

Using distance formula:

Length of A'D' = \sqrt{(2-(-2))^2+(0-0)^2} =\sqrt{(2+2)^2}= \sqrt{4^2} = 4

Therefore, the length of side A'D' is, 4 units.

Now, find the slope of CD and C'D'

where C =(2, 4) , D = (4, 0) , C' = (1, 2) and D' =(2,0)

using slope formula for any two points is given by:

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of CD = \frac{0-4}{4-2} = \frac{-4}{2} = -2

Similarly,

Slope of C'D' = \frac{0-2}{2-1} = \frac{-4}{2} = -2

Since, Sides CD and C'D' have same slope i.e, -2

Scale factor(k) states that every coordinate of the original figure has been multiplied by the scale factor.

  • If k > 1, then the  image is an enlargement.
  • if 0<k< 1, then the image is a reduction.
  • If k = 1, then the figure and the image are congruent.

The rule for dilation with scale factor(k) is;

(x, y) \rightarrow (kx , ky)

To find the scale factor:

A = (-4, 0) and A' = (-2, 0)

(-2, 0) \rightarrow (-4k , 0)

On comparing we ghet;

-4k = -2

Divide -4 both sides we get;

k = \frac{1}{2}

∴ The Scale factor is, k = \frac{1}{2}

Since, k < 1 which implies the image is a reduction.

Therefore, the statements which are true regarding about trapezoids are;

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

6 0
3 years ago
In ∆GHI and ∆JKL, GH = JK, HI = KL, GI = 9’, m∠H = 45°, and m∠K = 65°. Which of the following is not possible for JL: 5’, 9’ or
Aliun [14]

Answer:

hello

Step-by-step explanation:

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2 years ago
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tino4ka555 [31]
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median<span>" is the "middle" value in the list of numbers.</span>
3 0
3 years ago
Does 3 work as a solution to the following inequality? 2n &gt; 6
Ksju [112]

Answer:

No.

Step-by-step explanation:

If n=3 the only thing you get is 6, which is not more than 6.

5 0
3 years ago
Write and simplify an expression to represent the perimeter of the triangle shown. Then find the value of x if the perimeter is
Pavlova-9 [17]

Answer:

7

Step-by-step explanation:

x +4+2x+1+3x-2 = perimeter of triangle.

(6x +3)ft = perimeter

given perimeter = 45feet

hence,

6x + 3 = 45

6x = 42

x = 7

Hope it helped!! plz mark brainliest!! have a good day !! :)

7 0
3 years ago
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