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2 years ago

How do you solve 2^5? Explain using academic vocabulary

Mathematics

1 answer:

anastassius [24]2 years ago

6 0

Answer:

well if its 2*5 then its 10 because you have to count by 5's two times and you'll get 10. I hope this helps. :3

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Find the area of the figure. use 3.14 for pi

Elodia [21]

Answer:

33.29

Step-by-step explanation:

A=πr^2

A=π2^2=12.57

12.57/2=6.29

7-4=3

3x2=6

6/2=3

4x6=24

6.29+3+24=33.29

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2 years ago

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Anyone wana zoom with me

DochEvi [55]

Answer:

maybe

Step-by-step explanation:

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3 years ago

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Y=-0.05x^2+4.5x-6.5 pls help to solve

givi [52]

Following with the extra hint that x = 82.03 m

There are 2 ways to approach the question, but although I prefer to group up x first before plugging value, having that -0.05x^2 to group up is too annoying:

Plug x = 82.03

=> Y = -0.05*(82.03^2) + 4.5*82.03 - 6.5
= -336.446045 + 369.135 - 6.5
= 26.188955 m

Please take the time and understand the answer instead of just looking at the final result.

Also I know the number is very long, but that's the question's fault. <span>¯\_(ツ)_/¯</span>

6 0

2 years ago

Help geometry B, the last option is 260 degrees

Leto [7]

Answer:

Q + S = 360 - 55 - 45 = 260

Q = S

=> Q = 260/2 = 130

C is correct

5 0

2 years ago

A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s

ANTONII [103]

<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula. We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

We are given the function:

$h=-5t^{2}-3t+38$

Where,

$a=-5\\b=-3\\c=38$

Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$

Since negative time does not exists, the ball will hit the ground after:

$t=2.473s=2.47s$

Have a nice day!

4 0

2 years ago

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