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Dima020 [189]
3 years ago
5

How do you solve 2^5? Explain using academic vocabulary

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

well if its 2*5 then its 10 because you have to count by 5's two times and you'll get 10. I hope this helps. :3

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Factiorize; y*2-4,is the question​
Viktor [21]

Answer:

(y - 2)(y + 2)

standard factorization!

tadah

4 0
2 years ago
How many different permutations can you make with the letters in the word s e v e n t e e n ? A. 7,560 B. 17! C. 15,120 D. 3,780
Bess [88]

I'm not 100% sure if I'm doing it the right way, but I think the answer is the factorial of the number of letters divided by the factorials of the number of elements of each kind of element (in this case, the same letters)


9!/1!4!1!2!1!

= 9 · 8 · 7 · 6 · 5 · 4!/4!2!

= 9 · 8 · 7 · 6 · 5/2

= 9 · 4 · 7 · 6 · 5

= 63 · 120


= 7,560 permutations

8 0
3 years ago
Read 2 more answers
A restaurant makes pizzas with 6-inch diameters ad 12-inch diameters. Which of the following statement is true?
a_sh-v [17]

Answer:

The correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

Step-by-step explanation:

The area (A) of each pizza is given by:

A = \pi r^{2}

Where:

r: is the radius

For the 12-inch pizza we have:

A_{12} = \pi (\frac{12 inch}{2})^{2} = 113.1 inch

And for the 6-inch pizza we have:

A_{6} = \pi (\frac{6 inch}{2})^{2} = 28.3 inch

The ratio between A₆ and A₁₂ is:

\frac{A_{6}}{A_{12}} = \frac{28.3 inch}{113.1 inch} = 0.25 = \frac{1}{4}

Hence:

A_{6} = \frac{A_{12}}{4}

Therefore, the correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

I hope it helps you!            

4 0
3 years ago
Help meh pls
Iteru [2.4K]
Its 1+20x because you would subtract 2-1-=1 and 35x-15x=20x im sorry this is the real correct answer


4 0
3 years ago
Read 2 more answers
What is the average speed if Time = 3 Distance = 90
Natasha2012 [34]
Speed= distance divided by time. The answer is 30, and im assuming miles per hour. Hope this helps
6 0
3 years ago
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