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Dima020 [189]
3 years ago
5

How do you solve 2^5? Explain using academic vocabulary

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

well if its 2*5 then its 10 because you have to count by 5's two times and you'll get 10. I hope this helps. :3

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W+3 3/8=1 5/6 what is the answer
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W + 3 3/8 = 1 5/6;

W = 1 5/6 - 3 3/8;

W = 11/6 - 27/8;

W = 11/(2*3) - 27/(2*4);

W = (11*4 - 27*3)/(2*3*4);

W = (44 - 81)/24;

W = -37/24 = -1 13/24;

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Step-by-step explanation:

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The solution is attached as a word file.

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3 years ago
Consider he function f(x)=2x-4 a.find the inverse of (x) and name it g(x) . Show your work <br /><br /> B. Use funct
inna [77]

A.\\f(x)=2x-4\to y=2x-4\\\\\text{change x to y and y to x}\\\\x=2y-4\\\\\text{solve for y}\\\\2y-4=x\qquad|+4\\\\2y=x+4\qquad|:2\\\\y=\dfrac{1}{2}x+2\\\\f^{-1}(x)=g(x)=\dfrac{1}{2}x+2\\B.\\\text{Verifying if two functions are inverses of each other is a simple two-step process.}\\1.\ \text{Plug}\ f(x)\ \text{into}\ g(x)\ \text{and simplify}\\2.\  \text{Plug}\ g(x)\ \text{into}\ f(x)\ \text{and simplify}\\\\If\ g[f(x)]=f[g(x)]=x,\ then\ functions\ are\ inverses\ of\ each\ other.

f(x)=2x-4,\ g(x)=\dfrac{1}{2}x+2\\\\g[f(x)]=\dfrac{1}{2}(2x-4)+2=\dfrac{1}{2}(2x)+\dfrac{1}{2}(-4)+2=x-2+2=x\\\\f[g(x)]=2\left(\dfrac{1}{2}x+2\right)-4=2\left(\dfrac{1}{2}x\right)+2(2)-4=x+4-4=x\\\\\text{Since the results above came out OK, both}\ x,\text{ then we can claim}\\\text{that functions f (x) and g (x) are inverses of each other.}

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4 years ago
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