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monitta
3 years ago
10

Mrs. Myles gave the same test to both her first and third period class. In first period, the mean was 75 and the range was 30. I

n third period, the mean was 85 and the range was 50. Which is a true statement?
A) Most of third period scored in the 80's.
B) More people had a score in the 70's in first period.
C) On average, third period did better than first period.
D) On average, first period did better than third period.
Mathematics
2 answers:
Natalija [7]3 years ago
6 0
The right answer for the question that is being asked and shown above is that: "<span>C) On average, third period did better than first period. " I</span>n third period, the mean was 85 and the range was 50. The statement that is true is that <span>C) On average, third period did better than first period. </span>
Stella [2.4K]3 years ago
3 0

Answer:

C) On average, third period did better than first period

Step-by-step explanation:

Usa test prep

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Alex17521 [72]

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Answer:

  C.  50°

Step-by-step explanation:

The angle whose tangent is 1.19 is ...

  arctan(1.19) ≈ 49.9585° ≈ 50°

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3 years ago
Quick algebra 1 question for 50 points!
Otrada [13]

The number of songs that Deante' would have downloaded during month 9 is 58 songs.

<h3>What is a regression line?</h3>

A regression line is a statistical line that best describes the behavior of a data set and such, it is a line that best fits a set of data.

By using Microsoft excel to plot the data on a scatter plot, we can logically deduce that line of best fit for the songs downloaded is given by:

y = 2.03x + 39.7

Thus, the number of songs that Deante' would have downloaded during month 9 is:

y = 2.03(9) + 39.7

y = 18.27 + 39.7

y = 57.97 ≈ 58 songs.

Read more on regression here: brainly.com/question/26059078

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7 0
2 years ago
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A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample
leva [86]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.25 represent the population standard deviation

n represent the sample size (variable of interest)  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

8 0
4 years ago
Did I get it right????
Bingel [31]

Answer:

The answer is actually 105 m squared

Step-by-step explanation:

The area of a rectangle is the length times the width

The length is 7 and width is 15

7 x 15 = 105

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Murrr4er [49]

e^{\ln x}=x\\\\ e^{\ln 5}=5

7 0
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