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2 years ago

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Mathematics

1 answer:

Andru [333]2 years ago

8 0

The friction force exerted on the 2400kg car is 9408 Newtons

<h3>What force will be exerted on the 2400kg car?</h3>

First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:

F = k*M

Where F is the force, M is the mass and k is the constant of proportionality.

We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:

6272N = k*1600kg

Solving for k we get:

k = (6272N)/(1600 kg) = 3.92 N/kg

Then the proportional relationship is:

F = (3.92 N/kg)*M

So if M = 2400kg, we have:

F = (3.92 N/kg)*2400kg = 9408 N

So the friction force exerted on the 2400kg car is 9408 Newtons

If you want to learn more about proportional realtions:

brainly.com/question/12242745

#SPJ1

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The ratio of the height of two similar pyramids is 4:7. The volume of the smaller pyramid is 1,331cm, to the nearest whole numbe

IRISSAK [1]

Answer:

The volume of the larger pyramid is equal to $7,133\ cm^{3}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

In this problem, the ratio of the height is equal to the scale factor

$z=\frac{4}{7}$

step 2

Find the volume of the larger pyramid

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the smaller pyramid

y----> volume of the larger pyramid

$z^{3}=\frac{x}{y}$

we have

$z=\frac{4}{7}$

$x=1,331\ cm^{3}$

substitute

$(\frac{4}{7})^{3}=\frac{1,331}{y}\\ \\(\frac{64}{343})=\frac{1,331}{y}\\ \\y=343*1,331/64\\ \\y=7,133\ cm^{3}$

8 0

3 years ago

Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.

Leona [35]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: flexural strength of concrete beams.

Data:

7.3 6.8 8.6 9.7 11.6 9.7 6.8 7.7 11.8 7.4 8.1 8.7 6.3 7.9 7.0 7.9 7.8 6.5 6.3 7.0 7.5 7.7 7.2 11.3 9.0 10.7 5.1

The point estimate of the mean value is the sample mean. You calculate it using the following formula:

X[bar]= ∑X/n= 219.40/27= 8.1259≅ 8.13

b)x

The point estimate that divides the sample in 50%-50% is the measure of central tendency called Median(Me).

To reach the median you have to calculate it's position (PosMe)

For uneven samples PosMe= (n+1)/2= (27+1)/2= 14 ⇒ This means that the Median is the 14th observation of the data set.

So next is to order the data from lower to heighest and identify the value in the 14th position:

5,1 ; 6,3; 6,3; 6,5 ; 6,8; 6,8; 7; 7; 7,2; 7,3; 7,4 ; 7,5 ; 7,7 ; 7,7 ; 7,8 ; 7,9 ; 7,9 ; 8,1 ; 8,6 ; 8,7 ; 9 ; 9,7 ; 9,7 ; 10,7 ; 11,3 ; 11,6 ; 11,8

Me= 7.7

d) x tilde

The point estimate of the population standard deviation is the sample standard deviation. The standard deviation is the square root of the variance, so the first step is to calculate the sample variance:

$S^2= \frac{1}{n-1}*[sumX^2-\frac{(sumX)^2}{n} ]$