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abruzzese [7]
2 years ago
13

What is the range of the function y=3√x+8? -∞xy<∞ -8 0≤y<∞ 2≤y<∞

Mathematics
1 answer:
sdas [7]2 years ago
6 0

The range of the function the as given in the equation is; -∞ ≤ y < ∞.

<h3>What is the range of the function?</h3>

It follows from the task content that the function given is; y=3√x+8.

On this note, it follows that the range of the function is the set of all possible outputs, y values and in this case is; -∞ ≤ y < ∞.

It therefore follows that the range of the function is as indicated above as all X-values (domain) must be positive and the square root of x yields a positive or negative real number.

Read more on range;

brainly.com/question/1579288

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Find the surface area of the cone in terms of pi. 15cm 3cm
BaLLatris [955]

Answer:

The surface area of cone = 54π cm²

Step-by-step explanation:

Given ;

Radius = 3 cm

slant height = 15cm

The surface area of cone = πr ( r + l )

=> π × 3 ( 3 + 15)

=> π × 3 ( 18)

=> 54 π cm²

6 0
2 years ago
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A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
3 years ago
Two sides of a triangle measure 20 cm and 30cm. What is the third side?
Naily [24]
Hi there!

It depends on what angles there are, and how many degrees are in each angle. In order to figure this problem out, you need to know at least one angle ;)

Hope this helps!
3 0
3 years ago
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Algebra Linear Equations City Task (1)
Bogdan [553]

Answers:

1) Graph Line 1

a) Graph: Please, see the attached graph.

b) (Line 1) Main Street (Equation in slope intercept form): y=(1/3)x+4  

2) Graph Line 2

a) Graph: Please, see the attached graph.

b) Y intercept: (0,10)  

c) X intercept: (5,0)

d) (Line 2) Street Equation in Standard Form: y+2x=10

3) Grap Line 3

a) Graph: Please, see the attached graph.

b) (Line 3) Street Equation in Point Slope Form: <u>y-3=(5/3)(x+3)</u>

Street Equation in Slope Intercept Form: <u>y=(5/3)x+8</u>


Solution:

1) Graph Line 1: (Main Street)

a) Graph the line formed from the two given points (9,7) (-9,1)

Please, see the attached graph.

b) Find the street equation in slope intercept form

P1=(9,7)=(x1,y1)→x1=9, y1=7

P2=(-9,1)=(x2,y2)→x2=-9,y2=1

m=(y2-y1)/(x2-x1)

m=(1-7)/(-9-9)

m=(-6)/(-18)

m=6/18

m=(6/6)/(18/6)

m=1/3

Point Slope form:

y-y1=m(x-x1)

y-7=(1/3)(x-9)

Slope Intercept Form:

y-7=(1/3)x-(1/3)(9)

y-7=(1/3)x-(1)(9)/3

y-7=(1/3)x-9/3

y-7=(1/3)x-3

y-7+7=(1/3)x-3+7

y=(1/3)x+4


2) Graph Line 2

a) Graph the line given the x and y intercepts

y intercept: 10

x intercept: 5

Please, see the attached graph

b) Y intercept  

y intercept: b=10

Y intercept: (0,b)→Y intercept: (0,10)

c) X intercept

x intercept: a=5

X intercept: (a,0)→X intercept: (5,0)

d) Find the Street Equation in Standard Form

P1=(0,10)=(x1,y1)→x1=0, y1=10

P2=(5,0)=(x2,y2)→x2=5, y2=0

m=(y2-y1)/(x2-x1)

m=(0-10)/(5-0)

m=(-10)/(5)

m=-2

Point Slope Form:

y-y1=m(x-x1)

y-10=(-2)(x-0)

y-10=(-2)(x)

y-10=-2x

Standard Form:

y-10+10+2x=-2x+10+2x

y+2x=10


3)  Graph Line 3

a) Graph the line given a point and the slope. (-3,3); m=5/3

Point 1: P1=(-3,3)=(x1,y1)→x1=-3, y1=3

Slope: m=5/3

m=dy/dx

5/3=dy/dx→dy=5, dx=3

Point 2: P2=(x2,y2)

x2=x1+dx→x2=-3+3→x2=0

y2=y1+dy→y2=3+5→y2=8

Point 2: P2=(x2,y2)→P2=(0,8)

Please, see the attached graph.

b) Find the Street Equation in Point Slope Form

Point Slope Form:

y-y1=m(x-x1)

y-3=(5/3)(x-(-3))

y-3=(5/3)(x+3)

Slope Intercept Form:

y-3=(5/3)x+(5/3)(3)

y-3=(5/3)x+(5)(3)/3

y-3=(5/3)x+15/3

y-3=(5/3)x+5

y-3+3=(5/3)x+5+3

y=(5/3)x+8

3 0
3 years ago
Which of the following is equivalent to square root of 8?
arlik [135]

Answer:

\sqrt{8} =\sqrt{4*2} =2\sqrt{2}

Step-by-step explanation:

The expression \sqrt{8} is a radical. To simplify pull out any perfect square factors.

\sqrt{8} =\sqrt{4*2} =2\sqrt{2}

Each of these expressions is equivalent.

4 0
3 years ago
Read 2 more answers
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