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vaieri [72.5K]
1 year ago
10

At a concert , there was three grades of seats available Grade A is the most expensive Grade B is the middle price and Grade C S

eats are The Cheapest The Ratio of seat ticket prices was A: B : C = 5 : 3 :2 if the cheapest seats the concert £16 what were the cost of the other seat types? example 5/10 , = 1/2 middle price = 3/10 cheapest = 2/10 = 1/5​
Mathematics
1 answer:
horsena [70]1 year ago
4 0

The cost of other seats £40 and £24.

<h3>What is ratio?</h3>

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Given ratio: A: B : C = 5 : 3 :2

let the common ratio be 'x'.

Grade A cost = 5x

Grade B cost = 3x

Grade C cost = 2x

cheapest seats the concert £16

So,

2x=16

x=8

Now, Grade A cost = 5x = 5*8 = £40

Grade B cost = 3x= 3*8 = £24.

Learn more about ratio here:

brainly.com/question/13419413

#SPJ1

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The maximum load of a horizontal beam that is supported at both ends varies jointly as the width and the height and inversely as
dezoksy [38]

Answer:

360kg

Explanation:

Here, we want to get the maximum load supported

From the first part of the question, we have it that:

The maximum load g, varies jointly with the width w and the height h, and inversely as the length l between the supports

Mathematically, we have that as:

g\text{ = k }\times\frac{wh}{l}

where k is the proportionality constant

Now, let us get the value of k

We substitute the first set of values as follows:

\begin{gathered} 360\text{ = }\frac{k\times0.1\times0.06}{6} \\  \\ k\text{ = 360,000 }\frac{kg}{m} \end{gathered}

Now, using this value of k, we want to get the value of g

Mathematically, we have that as:

g\text{ = }\frac{360,000\times0.2\times0.08}{16}\text{ = 360 }kg

8 0
1 year ago
A solid right pyramid has a square base. The length of the base edge is4 cm and the height of the pyramid is 3 cm period what is
Illusion [34]

Answer:

The volume of this pyramid is 16 cm³.

Step-by-step explanation:

The volume V of a solid pyramid can be given as:

\displaystyle V = \frac{1}{3} \cdot b \cdot h,

where

  • b is the area of the base of the pyramid, and
  • h is the height of the pyramid.

Here's how to solve this problem with calculus without using the previous formula.

Imaging cutting the square-base pyramid in half, horizontally. Each horizontal cross-section will be a square. The lengths of these squares' sides range from 0 cm to 3 cm. This length will be also be proportional to the vertical distance from the vertice of the pyramid.

Refer to the sketch attached. Let the vertical distance from the vertice be x cm.

  • At the vertice of this pyramid, x = 0 and the length of a side of the square is also 0.
  • At the base of this pyramid, x = 3 and the length of a side of the square is 4 cm.

As a result, the length of a side of the square will be

\displaystyle \frac{x}{3}\times 4 = \frac{4}{3}x.

The area of the square will be

\displaystyle \left(\frac{4}{3}x\right)^{2} = \frac{16}{9}x^{2}.

Integrate the area of the horizontal cross-section with respect to x

  • from the top of the pyramid, where x = 0,
  • to the base, where x = 3.

\displaystyle \begin{aligned}\int_{0}^{3}{\frac{16}{9}x^{2}\cdot dx} &= \frac{16}{9}\int_{0}^{3}{x^{2}\cdot dx}\\ &= \frac{16}{9}\cdot \left(\frac{1}{3}\int_{0}^{3}{3x^{2}\cdot dx}\right) & \text{Set up the integrand for power rule}\\ &= \left.\frac{16}{9}\times \frac{1}{3}\cdot x^{3}\right|^{3}_{0}\\ &= \frac{16}{27}\times 3^{3} \\ &= 16\end{aligned}.

In other words, the volume of this pyramid is 16 cubic centimeters.

5 0
2 years ago
The sum of 1/6, 2/3, and 1/4 is
Oxana [17]
First, make all the denominators same.
Then calculate.
Hopefully this helps :D

3 0
3 years ago
In the following equation what would 8×6 be equaled to
pochemuha

Step-by-step explanation:

Hi mate I am new to this app

8 0
3 years ago
Read 2 more answers
Sin4u=2sin 2u cos 2u​
yKpoI14uk [10]

Answer:

If you've learnt sin(A+B) = sinAcosB + cosAsinB,

sin(4u)

= sin(2u+2u)

= sin(2u)cos(2u) + cos(2u)sin(2u)

= 2 sin(2u) cos(2u).

4 0
2 years ago
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