3 years ago

Hard please help. :/

Mathematics

2 answers:

inysia [295]3 years ago

8 0

Answer:

Step-by-step explanation:

since it equals to 90 you subtract that with 32

which gives you 58

kakasveta [241]3 years ago

5 0

Answer:58

Step-by-step explanation:

You might be interested in

-c = 3abc-a; solve for c

emmainna [20.7K]

Answer:

C= 12

Step-by-step explanation:

8 0

3 years ago

A water sprinkler has a range of 5 meters as shown. The jet of water from the sprinkler sweeps out at an angle of 85° as the noz

telo118 [61]

I found the image that accompanied this problem.
We need to solve for the area of the sector.

A = n/360 * π * r²
A = 85/360 * 3.14 * 5²
A = 0.2361 * 3.14 * 25
A = 18.5347

Answer is C. 18.5 square meters.

6 0

3 years ago

Read 2 more answers

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.

taurus [48]

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

m∠S=90°
m∠R=29°,
SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

$Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\$Cross multiply$\\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\$=10.5 ft (to the nearest tenth of a foot)$