A team of runners is needed to run a 1/4-mile relay race. If each runner must run 1/16 mile, how many runners will be needed

Mathematics

1 answer:

inysia [295]2 years ago

7 0

4 runners hope this helps

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The Orchard Cafe has found that about 3% of the diners who make reservations don't show up. If 83 reservations have been made, h

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Answer:

$\mu = 80.51\\\sigma = 1.56$

Step-by-step explanation:

We are given the following information in the question:

Percentage of of the diners who make reservations don't show up = 3%

Number of reservations = 83

Thus, we are given a binomial distribution with n = 83 and p = 0.97

$X\sim \text{ Binom}(p = 0.97, n = 83)$

$\mu = np = (83)(0.97) = 80.51$

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The standard deviation of this distribution is 1.56

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Eric and Mark were at a ball game and visited the concession stand. They each got a hamburger, and Mark got lemonade and some co

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So here is the answer. Given that both Eric and Mark got a hamburger which is $4 each. Mark got a lemonade and some cotton candy which costs $5.
So this gives them a total of $4, $4, $5, $?(lemonade). Partial sum is $13 without the lemonade. Since Eric got a $2, the total bill was deducted with $2 and the rest of the amount is $14.50. Therefore, the total bill would have been $16.50. So $16.50 minus $13 (partial sum) is $3.50. So the lemonade costs $3.50. Hope this helps.

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