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2 years ago

Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form.

Mathematics

1 answer:

hammer [34]2 years ago

3 0

The given sequence is a geometric sequence with a common ratio of 3.

<h3></h3><h3>Which type of sequence do we have here?</h3>

A geometric sequence is a sequence where the quotient between any pair of consecutive terms is a constant, called the common ratio.

Here we have the sequence:

3, 9, 27, ...

The quotient between the first two terms is:

9/3 = 3

The quotient between the third and second terms is:

27/9 = 3.

So yes, we conclude that this is a geometric sequence, where the common ratio is 3.

If you want to learn more about geometric sequences:

brainly.com/question/1509142

#SPJ1

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A story owner wants to prepare 100 lb of a candy mix that she will she for $1.36 per lb. She mixes 20 lb of jelly beans that cos

faust18 [17]

Answer:

1.65

Step-by-step explanation:

100 pounds of the mixture = 1.36 * 100 = 136 dollars.

She uses 20 pounds of jelly beans that cost

20 * .20 = 4.00

136 - 4 = 132 dollars left for 80 pounds of sugar candies.

80 pounds = 132 pounds of sugar candies.

1 pound = x

80/1 = 132 / x Cross multiply

80x = 132

x = 132 / 80

x = 1.65 / per pound

7 0

3 years ago

8) A school community had planned to reduce the number of grade 9 students per class room by constructing additional class rooms

Allisa [31]

Step-by-step explanation:

Let "c" be the original number of classrooms.

The 1200/c was the original number of students per classroom.

----

Equation:

1200/(c-4) = (1200/c)+10

Multiply thru by c(c-4)

---

1200c = 1200(c-4)+10c(c-4)

---

1200c = 1200c-4800 + 10c^2-40c

----

10c^2-40c-4800 = 0

c^2-4c-480 = 0

Factor:

(c-24)(c+20) = 0

---

Positive solution:

c = 24 (# of classrooms originaly planned)

7 0

3 years ago

If you meet five classmates, what is the probability that three are female?

klasskru [66]

Answer:

3/5 is probability of female out of 5 classmates.

hope it helps

<h3>stay safe healthy and happy.</h3>

5 0

3 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Natasha2012 [34]

Answer:

$x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$ are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

$2x^2-10x-3$

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

$x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}$

General form of quadratic equation is $ax^2+bx+c$

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

$D=\sqrt{(-10)^2-4(2)(-3)}$

$\Rightarrow D=\sqrt{100+24}=\sqrt{124}$

Now substituting D in $x=\frac{b^2\pm\sqrt{D}}{2a}$ we get

$x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}$

$x=\frac{100\pm\sqrt{124}}{4}$

$x=\frac{100\pm2\sqrt{31}}{4}$

$x=\frac{50\pm\sqrt{31}}{2}$

Therefore, $x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$

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3 years ago

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DerKrebs [107]

Answer:

63.0769230769

Step-by-step explanation:

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3 years ago

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