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dexar [7]
4 years ago
8

A week before an election, 15,00 people were asked who they planned to vote for. Of the people that asked, 45% said they planned

to vote for candidate x, and 38 said they planned to vote for candidate y. The rest said they had not yet decided. How many of the people that were asked have not yet decided who they plan to vote for?
Mathematics
2 answers:
VikaD [51]4 years ago
4 0

Answer:17%

Step-by-step explanation:

ad-work [718]4 years ago
3 0

Answer:

1050

Step-by-step explanation:

(15,000 x .45)-(15,000 x .38)

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What is 2.3g as a percentage of 5.98g ? (Round the nearest whole number)
Musya8 [376]

Answer:

38%

Step-by-step explanation:

2.3/5.98 x 100

= 0.38 x 100

= 38%

3 0
2 years ago
Lana makes $8 an hour plus $12 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week.
erik [133]
A. W = 8x
B. S = 8x + 12y
C. 8 * 40 = 320
    368 - 320 = 48
    48/12 = 4
Lana worked 40 regular hrs (320) + 4 overtime hrs (48) for a total of 368
3 0
3 years ago
Could anyone prove this question correct... pls... I will mark branliest for step by step solution.
Masja [62]

Answer:

C

Step-by-step explanation:

the answer is 15. hope this helps

8 0
3 years ago
Match the function in the left column with its period in the right column.
kiruha [24]

The results for the matching between function and its period are:

  • Option 1 - Letter D
  • Option 2 - Letter A
  • Option 3 - Letter C
  • Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi

Thus, the option 1 matches with the letter D.

2) Option 2

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}

Thus, the option 2 matches with the letter A.

3) Option 3

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi

Thus, the option 3 matches with the letter C.

4) Option 4

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0
2 years ago
A) Express 1400 as a product of its prime factors in index form.
Anarel [89]

Answer:

2 * 2 * 2 * 5 * 5 * 7

Step-by-step explanation:

7 0
3 years ago
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