Given sequence:
56, 63, 70,..., 329
First find the common difference:
d=a2-a1
d=63-56
d=7
Formula:
an=a1+(n-1)d
First find the number of terms.
329=56+(n-1)7
329=56+7n-7
329=49+7n
280=7n
40=n
or
n=40
We have to find 40-11=29 th term ( 11 th term from the end)
a29= 56+(29-1)7
a29=56+(28)7
a29=56+196
a29=252
Answer: 252 is 11th term from the end.
To write 1/12 as a decimal you would do 1 divided by 12. 1 goes into 12 0 times, giving you a 0 in the ones place. You would the do 120 divided by 12, giving you 10. Therefore, 1/12 as a decimal is 0.10, simplified to 0.1
Answer:
91
Step-by-step explanation:
Because the equation is equal to 91
Answer:
The expected number of tests necessary for the entire group of 304 people is 180.0325
Step-by-step explanation:
Probability of person being positive = p = 0.04
Probability of person being negative = q = 1-0.04=0.96
Number of people in each group = 19
We will use binomial over here
Probability of no test positive :

P( at least one tests positive) = 1-P( no one tests positive)= 1-0.460419201958= 0.539580798042
Expected number of tests for each group = 1(0.460419201958)+20(0.539580798042) = 11.2520351628
Number of groups =
Expected number of tests necessary for the entire group of 304 people:
=
=
=180.0325
Hence The expected number of tests necessary for the entire group of 304 people is 180.0325
Answer:
-3
Step-by-step explanation:
Because if you line them up without thinking about the celsius -3 is going to be the last after 0.
Extra: Here is them in chronological order -3,-2,-0.8,-1/10, 1/2, 0.8, 7