Factors of 36 that add up to -12
-6 and -6
<span>(x − 6)(x − 6)
</span>
Set them both to equal 0 and solve for x
x - 6 = 0
x - 6 = 0
x = 6
x = 6
Answer:
3x^4-18x^3+27x^2-12x
Step-by-step explanation:
Multiply the second paréntesis for each term of the first parentage
3x^2×(x^2-2x+1)-12x×(x^2-2x+1)
Multiply parentage by 3x^2
3x^4-6x^3+3x^2-12x×(x^2-2x+1)
Multiply the parentage by -12x
3x^4-6x^3+3x^2-12x^3+24x^2-12x
Group similar terms
3x^4-18x^3+27x^2-12x
A. How many kilowatt hours of electricity did the Smiths use during February?
Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February
b. How many kilowatt hours did they use during March?
Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March
Answer:
40 mph
Step-by-step explanation:
We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...
outbound speed : inbound speed = 4 : 3
These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...
4×10 mph = 40 mph
Paul's average speed on the outbound trip was 40 mph.
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The distance to the lake was 120 mi.
