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Travka [436]
2 years ago
13

Which graph represents the following system of inequalities?

Mathematics
1 answer:
Korolek [52]2 years ago
8 0

The graph of the two given system of inequalities y > 2x - 5

y < -3x is; Attached below

<h3>How to graph Inequalities?</h3>

We are given two inequalities;

y > 2x - 5

y < -3x

The graph that represents the 2 inequalities has been attached and from the graph, we see that;

  • The slope of the dotted line is negative

  • The x- intercept of the dotted line is the point (0,0)

  • The y- intercept of the dotted line is the point (0,0)

The solution of the system of inequalities is the shaded pink area between the two dotted lines.

Read more about Inequality Graphs at; brainly.com/question/13635292

#SPJ1

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IrinaVladis [17]

How sad, that you didn't include the list of choices.

The volume of the cone is    (1/3) x (π) x (radius²)  .

The volume of the sphere is  (4/3) x (π) x (radius³) .


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3 years ago
A large random sample of American students in seventh grade showed that 20%20\% 20% 20, percent of them were reading below grade
WITCHER [35]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] &lt; y0 &lt; [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
2 years ago
HELP PLEASE I'LL GIVE 30 POINTS!!!​
jasenka [17]

Answer:

x = 45

Step-by-step explanation:

Straight line has 180 degrees; so if you add all the angles up:

2x + x + x = 180

4x = 180

x = 45 degrees

6 0
3 years ago
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X2 + y2 + 6x – 2y+3 = 0?<br> What is the radius of a circle with the equation
ExtremeBDS [4]

Answer:

Step-by-step explanation:

hello : write this expression

X² + y² + 6x – 2y+3 = 0  in the standard form

(x²+6x) +(y²-2y) +3 = 0

(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0

(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0

(x+3)²+(y-1)² = 7(the standard form)

but : 7 = (√7)²

<h2>the radius is : √7</h2>

5 0
3 years ago
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