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2 years ago

John bought an antique model car priced at $72 she also had to pay 5% sales tax what was the total amount she paid

Mathematics

1 answer:

jeka942 years ago

4 0

Multiply $72 into 5% and that should give you an answer

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Which of the following is equivalent to (4x²)³ ?

Natalija [7]

$\left(4x^2\right)^3=4^3\left(x^2\right)^3=64x^{2\cdot3}=64x^6$

5 0

3 years ago

If X > 0 and y > 0 , then which quadrant holds the solutions ?

pantera1 [17]

Answer:

First Quadrant

Step-by-step explanation:

The quadrant in which both x and y are greater than 0 is the First Quadrant.

8 0

3 years ago

WHOEVER GETS RIGHT GETS BRAINLIEST!!

ozzi

Answer:

Answer B: min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note: Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term: it is 2.

Take half of that and square your result: (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x + 1 - 1 - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or f(x) = (x - 1)^2 - 6

Compare this to the standard form

f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B: min. value at -6.

3 0

2 years ago

What is 234x13+76=?<br>the explained comment get brainiest

Scorpion4ik [409]

Answer:

The answer is 3118

Step-by-step explanation:

First -> 234 x 13 = 3042

Second -> Add 76 to 3042

Equals out to -> 3118

Hope this helps!

7 0

2 years ago

Read 2 more answers

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

2 years ago