Ask question

Ask question

All categories

I am Lyosha [343]

3 years ago

6

Si Jose recarga su teléfono con ₡6000 y realiza 5 llamadas de 4 minutos, 3 llamadas de 6 minutos y manda 20 mensajes ¿cuanta rec

arga le queda si cada minuto de llamada cuesta ₡60 y cada mensaje ₡25?

1 answer:

xenn [34]3 years ago

8 0

Answer:

3220

Step-by-step explanation:

5x4=20

3x6=18

20+18=38

1=60

38x60=2280

20x25=500

2280+500=2780

6000-2780=3220

You might be interested in

What’s the area of the triangle??

viktelen [127]

Note that one side is 20 ft, and the other is 16.

This means that the side that is part of the triangle is 4 ft.

The measurement is still the same for the triangle's height.

Find the area of the rectangle:
24 x 16 = 384
Find the area of the triangle:
4 x 24 = 96

Add the two numbers together:

384 + 96 = 480

You're answer is (C)

hope this helps

5 0

3 years ago

Read 2 more answers

the coach for a basketball team wants to buy new shoes for her 12 players. super sport is offering a 20%discount on each pair of

Klio2033 [76]

Here are the calculations for Super Sport:

[12 ($72.50 x 0.8)] 1.065 = $741.24

Here is the math for Double Dribbles:

[12($54.75 x 1.09)] + (12 x $5.99) = $788.01

$788.01 - $741.24 = $46.77

The difference in price is $46.77.

6 0

2 years ago

10 to the power of 3 times what equals 630

vekshin1

10³ · x = 630
x = ?

10³ = 10 × 10 × 10 = 1,000

630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63

So we have:

10³ · 0.63 = 630

6 0

3 years ago

Read 2 more answers

What is the value of y

trapecia [35]

Answer:

$Here,\\Since~BC$ ║ $DE,\\$

[Corresponding Sides of similar triangles are proportional.]

$or, \frac{y}{2y} = \frac{3}{3y} \\or, \frac{1}{2} = \frac{1}{y}\\or, y=2$

4 0

2 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

2 years ago