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We will compare pairwise treatment with the help of t-statistic to find the best treatment.The t-statistic, which is used in statistics, measures how far a parameter's estimated value deviates from its hypothesized value relative to its standard error.We need to check if the treatments are effective in curing phobia.
First, we must determine whether there is a relationship between the type of treatment used and the final result (cure or not cure). We may examine this using the Chi-square test of association.In the second phase, we must determine if all therapies are the same or different if the alternative hypothesis—that is, whether there exists any kind of link between therapy and cure—is accepted.
We must perform a One-way ANOVA for the treatments in this case, assuming that all treatments are equal. If the null hypothesis is rejected in this instance, then the treatments differ. then, we go to step three.We will compare pairwise treatment with the help of t-statistic to find the best treatment.
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Answer:
<em>The amount of water in the reservoir at the beginning of second week</em>
<em></em><em></em>
Step-by-step explanation:
<u>Step(i):</u>-
<em>Given equation </em>
<em> w₀ = 300 and </em>
Put n =1
<u><em>Step(ii)</em></u>:-
<em>Put n =2</em>
<u><em>Conclusion:</em></u>-
<em>The amount of water in the reservoir at the beginning of second week</em>
<em></em><em></em>
<em></em>
Answer:
Option A: P(Male or Type B) > P(Male | Type B)
Step-by-step explanation:
Total Female = 85 type A, 12 type B ⇒ 97 Female.
Total Male = 65 type A, 38 type B ⇒ 103 Male
Total type A = 65 + 85 = 150
Total type B = 12 + 38 = 50
total number of people = 97 + 103 = 200
Then the probability would be:
P(Male | Type B) =
=
= 0.368
P(Male or Type B) =
=
=
=
= 0.575
Hence, P(Male or Type B) > P(Male | Type B)