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Rus_ich [418]
3 years ago
10

A candy store sells​ chocolate-covered almonds for ​$7.50 per pound and​ chocolate-covered peanuts for ​$5.00 per pound. The man

ager decides to make a bridge mix that combines the almonds with the peanuts. She wants the bridge mix to sell for ​$7.00 per​ pound, and there should be no loss in revenue from selling the bridge mix rather than the almonds and peanuts alone. How many pounds of​ chocolate-covered almonds and how many pounds of​ chocolate-covered peanuts are required to create 65​ pounds of bridge​ mix?
Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer:

32.5 lbs

Step-by-step explanation:

so divide 65 by 2 which will give you 32.5 it's eveny in half

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$\frac{(x+1)(x-3)}{x^{2}}

Solution:

Given expression:

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To solve this expression:

$\frac{\frac{36}{x^{2}}+\frac{36}{x}}{\frac{36}{x-3}}

Apply the fraction rule: $\frac{a}{\frac{b}{c}}=\frac{a \cdot c}{b}

      $=\frac{\left(\frac{36}{x^{2}}+\frac{36}{x}\right)(x-3)}{36}

Let us solve \frac{36}{x^{2}}+\frac{36}{x}.

Least common multiple of x^{2}, x is x^{2}.

Make the denominator same based on the LCM.

So that multiply and divide the 2nd term by x, we get

$\frac{36}{x^{2}}+\frac{36}{x}=\frac{36}{x^{2}}+\frac{36 x}{x^{2}}

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Now, multiply by (x - 3).

$\frac{36+36 x}{x^{2}}(x-3)= \frac{(36 x+36)(x-3)}{x^{2}}

$\frac{\left(\frac{36}{x^{2}}+\frac{36}{x}\right)(x-3)}{36}=\frac{\frac{(36 x+36)(x-3)}{x^{2}}}{36}

Apply the fraction rule: \frac{\frac{b}{c}}{a}=\frac{b}{c \cdot a}

                            $=\frac{(36x+36)(x-3)}{x^{2} \cdot 36}

                            $=\frac{36(x+1)(x-3)}{x^{2} \cdot 36}

Cancel the common factor 36.

                            $=\frac{(x+1)(x-3)}{x^{2}}

Hence the solution is \frac{(x+1)(x-3)}{x^{2}}.

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Answer:

<h2><em><u>See in attachment and Mark as brainleist please.</u></em></h2>

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Step-by-step explanation:

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