We are asked to determine the opening of the graph of the given equation y² + 16y - 4x + 4= 0. To answer this problem, we need to transform the equation into the standard form where all variable y and variable x are in opposite side such as shown below:
y² + 16y - 4x + 4 = 0
y² + 16y = 4x - 4
y² + 16y + 64 = 4x - 4 +64
(y + 8)² = 4x + 60
Then, the graph opens to the right.
Step-by-step explanation:
according to the graph, the correct answer is:
possitive : (-1, 2) and (6, oo)
negative : (-oo, -1) and (2, 6)
I believe the correct answer is B
Answer:
1st: -3 -5
_y+_
2 2
2nd -3y-5
____
x
Step-by-step explanation: