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otez555 [7]
3 years ago
15

A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path. which number line cor

rectly models this situation and the total number of distance markers?
Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Given :

A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.

To Find :

Which number line correctly models this situation and the total number of distance markers.

Solution :

It is given that their are markers every 1/4 part of mile.

So, their are 4 markers per mile.

Numbers of markers in 3 miles long path is :

n = 3\times 4\\\\n = 12

Therefore, the total number of distance markers in 3 mile path is 12.

Hence, this is the required solution.

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The equation line l is given by the equation y= 7/4x+3. line m goes through the point ( –1,4) and is perpendicular to line l whi
mr_godi [17]

We determine line m as follows:

*First, by theorem we have the following:

m_1=-\frac{1}{m_2}

Here m1 & m2 are the slopes of two perpendicular lines. For all lines that are perpendicular that is true, so we calculate the slope of line m using the slope of the function given [Which has a slope of 7/4]:

m_1=-\frac{1}{\frac{7}{4}}\Rightarrow m_1=-\frac{4}{7}

So, the slope of line m is -4/7. Now, using this slope and the point (-1, 4) we replace in the following expression:

y-y_1=m_1(x-x_1)

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y-4=-\frac{4}{7}(x-(-1))\Rightarrow y-4=-\frac{4}{7}x-\frac{4}{7}\Rightarrow y=-\frac{4}{7}x+\frac{24}{7}

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8 0
1 year ago
2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac
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Answer:

P(disease/positivetest) = 0.36116

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NT : ''The test is negative''

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Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

P(B) >0

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

P(I)=0.025

P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975

P(PT/I)=0.904\\P(PT/NI)=0.041

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=0.904

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

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0.041=P(PT∩ NI)/0.975

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P(PT∩ NI) = 0.039975

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P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116

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