Answer:
An autosomal dominant gene is one that occurs on an autosomal (non-sex determining) chromosome. As it is dominant, the phenotype it gives will be expressed even if the gene is heterozygous.
The chances of an autosomal dominant disorder being inherited are 50% if one parent is heterozygous (NL) for the mutant gene and the other is homozygous for the normal (NN), or 'wild-type', gene. This is because the offspring will always inherit a normal gene from the parent carrying the wild-type genes, and will have a 50% chance of inheriting the mutant gene from the other parent. If the mutant gene is inherited, the offspring will be heterozygous for the mutant gene, and will suffer from the disorder. If the parent with the disorder is homozygous for the gene, the offspring produced from mating with an unaffected parent will always have the disorder.
Explanation:
Answer:
The steps involves making hypothesis, deriving predictions from the logical consequences and then carrying out experiments based on those predictions.
Explanation:
Step 1: make a observation .
Step 2: Formulate a statement or question.
Step 3: Form the hypothesis .
Step 4: make a prediction based on the hypothesis.
Step 5: test the hypothesis whether its true or not.
Step 6: use the results to conclude the experiment.
B. Segregation.
I have the same question and answered it and this is what it told me. I think it should be right.
Answer:
The tRNA is released from the E site of the ribosome and the elongation process finishes while the termination process starts.
Explanation:
When the translocation process is finished the tRNA that is in the E site of the ribosome is released and the A site of the ribosome reads a stop codon in the mRNA in order to finish the elongation process and start with the termination process. In the termination process a termination factor joins the stop codon, the ribosomal subunits split apart, the protein and the tRNA dissociate from one another and the tARN is not in the P site of the ribosome anymore.
