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viktelen [127]
2 years ago
11

3x

bsmiddle" class="latex-formula">
Mathematics
1 answer:
Licemer1 [7]2 years ago
3 0

The solution to the quadratic equation 3x² + 8x - 10 by using the quadratic formula is x = 0.927 or -3.594

<h3>Solving quadratic equations.</h3>

Quadratic equations are algebraic expressions that are represented in the power of the second degree. They usually take the form ax² + bx + c

From the given information, we are to solve the quadratic equation:

  • 3x² + 8x - 10

Using the quadratic formula:

\mathbf{=\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}

where:

  • a = 3
  • b = + 8
  • c = - 10

\mathbf{= \dfrac{-(8)) \pm \sqrt{(8)^2 - 4(3 \times (-10))}}{2(3)}}

\mathbf{= \dfrac{-(8)) \pm \sqrt{64 -4 (-30)}}{6}}

\mathbf{= \dfrac{-(8)) \pm \sqrt{64+120}}{6}}

x = 0.927 or -3.594

Learn more about solving quadratic equations here:

brainly.com/question/8649555

#SPJ1

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Answer:

p=(0,2) q=(0.5,0)

Step-by-step explanation:

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3 years ago
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If y varies directly as x and y = 3 when x = - 9, then find x when y = 5.
Rus_ich [418]

Answer:

d. - 15

Step-by-step explanation:

The equation for direct variation is

y = kx

We know y =3 when x = -9

3 = k(-9)

Divide by -9

3/-9 = -9k/-9

-1/3 = k

The equation is then

y = -1/3 x

We know y = 5

5 = -1/3 x

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3 years ago
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Expand ( x - 1/x^2)^4
emmainna [20.7K]

Answer:

We want to expand the expression:

(x - \frac{1}{x^2} )^4

We can just do it by brute force, this is:

First, rewrite our expression as the product of two square factors:

(x - \frac{1}{x^2} )^4 = (x - \frac{1}{x^2} )^2*(x - \frac{1}{x^2} )^2

Now we can expand each one these two factors:

(x - \frac{1}{x^2} )^2 = (x - \frac{1}{x^2} )*(x - \frac{1}{x^2} ) = x^2 + \frac{1}{x^4} -2*x*\frac{1}{x^2}

That can be simplified to

x^2 - \frac{2}{x} + \frac{1}{x^4}

Now we can replace that in our original expression to get:

(x^2 - \frac{2}{x} + \frac{1}{x^4})*(x^2 - \frac{2}{x} + \frac{1}{x^4})

Now we can expand that last product, to get:

(x^2)^2 + 2*(x^2)*(-\frac{2}{x} ) + 2*(x^2)*(\frac{1}{x^4}) + 2*(\frac{-2}{x})*(\frac{1}{x^4}) + (\frac{-2}{x}  )^2 + (\frac{1}{x^4})^2

We can simplify that to:

x^4 - 4x + 2x^2 - \frac{4}{x^5}  + \frac{4}{x^2} + \frac{1}{x^8}

That is the expanded expression.

6 0
3 years ago
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