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irina [24]
2 years ago
6

Multiply. (9x−2)(3x−8) Enter your answer, in standard form, in the box.

Mathematics
2 answers:
Brums [2.3K]2 years ago
6 0

Answer:

27 x 2 −78 x + 16

Step-by-step explanation:

Trava [24]2 years ago
6 0

Answer:

27x^2-78x+16

Step-by-step explanation:

took the test

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There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the
algol13
The probability is 3/14. There are 2 multiples of 4 in 14, which is 8 and 12. There is only 1 multiple of 6 in 14 which is 12. 1+2=3. It is possible outcomes over total outcomes so 3/14.
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2 years ago
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Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.
Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

A=s^2 where s is the side length.

We know,  1 \text{ hectare}=10,000\ m^2

1) The area of square plot is 7 hectare.

Area in meter square is A=7\times 10000=70000\ m^2

Substitute the value in the formula,

70000=s^2

\sqrt{70000}=s

264.57=s

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is A=12\times 10000=120000\ m^2

Substitute the value in the formula,

120000=s^2

\sqrt{120000}=s

346.41=s

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is A=30\times 10000=300000\ m^2

Substitute the value in the formula,

300000=s^2

\sqrt{300000}=s

547.72=s

Side nearest to 1/10th meter is 547.7 meter.

5 0
2 years ago
Jaylen bed is 6 feet long and his desk is 3 feet long. he wants to leave a two foot space between his bed and desk. if there is
Montano1993 [528]
No, he would need 132 inches
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Work out angle bxc. give a reason for each angle you work out
Rus_ich [418]

Answer:

∠ BXC = 70°

Step-by-step explanation:

∠ XBC and ∠ AXY are corresponding angles and are congruent, then

∠ XBC = 55°

Since XB = XC , then Δ XBC is isosceles and the 2 base angles are congruent.

∠ BXC = 180° - (55 + 55)° ← angle sum of triangle

∠ BXC = 180° - 110° = 70°

7 0
2 years ago
Please help me !!!
kati45 [8]
23)~75r^2-48=3(25r^2-16)=3(5r-4)(5r+4)\\\\
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25)~m^3n-mn^3=mn(m^2-n^2)=mn(m-n)(m+n)\\\\
26)~6a^3-24ab^2=6a(a^2-4b^2)=6a(a-2b)(a+2b)\\\\
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29)~x^3+9x^2-52x=x(x^2+9x-52)=x(x-4)(x+13)\\\\
30)~4y^3+4y^2-120y=4y(y^2+y-30)=4y(y-5)(y+6)
5 0
3 years ago
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