What are the ratios and is this table proportional

What is the longest line segment that can be drawn in a right rectangular prism that is 15cm long, 13cm wide, and 8cm tall?

Effectus [21]

Answer:

15cm long

Step-by-step explanation:

8 0

2 years ago

Angle G is a circumscribed angle of circle E. Major arc FD measures 280°.

mixer [17]

Answer:

The answer is 40°

Step-by-step explanation:

Solution

Now,

The Measure of major arc FD = 280°

Thus,

One complete angle measure 360°

Then

m∠FED = 360 - 180

m∠FED = 80°

Thus,

FE = DE ( the same circle Radius)

∠EFD = ∠EDF ( opposite angles to equal sides are equal)

Now

Applying angle sum property of a triangle in ΔEFD

∠EFD + ∠EDF + ∠FED = 180°

∠EFD + ∠EFD + 80 = 180

2∠EFD = 100

∠EFD = 50°

Hence, GF is tangent to the circle and the tangent always make right angles with the radius of the circle.

∠EFG = 90°

∠GFD + ∠EFD = 90°

∠GFD + 50 = 90

∠GFD = 40°

Therefore, The measure of the angle GFD is 40°

8 0

3 years ago

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A prism is completely filled with 3996 cubes that have edge lengths of 13 in. What is the volume of the prism? Enter your answ

ANEK [815]

First, solve for the volume of each cube through the equation,
V = e³
Substituting the known value,
V = (13 in)³ = 2197 in³
Then, multiply this volume by the number of cubes. Thus, the total volume of the prism,
V = (2197 in³)(3996)
V = 8,779,212 in³

3 0

3 years ago

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(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

2 years ago

What is 45/117 as a simplified fraction

qaws [65]

5/13
45÷9=5
117÷9=13..

6 0

3 years ago

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