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lesya692 [45]
2 years ago
6

Which era marked a switch from agricultural practices to industrial practices?

Computers and Technology
1 answer:
sashaice [31]2 years ago
7 0

The Industrial Revolution is the era that is marked a switch from agricultural practices to industrial practices.

<h3>What was the Inductrial revolution?</h3>

The Industrial revolution is the transition period between 1820 to 1840. The era was the development of new industries and manufacturing of products and goods in Great Britain.

Thus, the Industrial Revolution is the era that is marked a switch from agricultural practices to industrial practices.

Learn more about Inductrial revolution

brainly.com/question/1617908

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Answer:

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Explanation:

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4. What is the package name in which the Scanner class resides?
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A certain string-processing language offers a primitive operation which splits a string into two pieces. Since this operation in
Nostrana [21]

Answer:

Explanation:

First we define define cost(i,j) to be the cost of cutting the string from index i to j. Then,

cost(i,j) = min {length of substring + cost(i,k) + cost(k,j) where i < k < j}

void  s_cut()    

 {

   int l,p;

   int temp=0;

   //ArrayList<Integer> al = new ArrayList<Integer>();

   int al[];

   Scanner s=new Scanner(System.in);

   int table[][];

   ArrayList<Integer> values[][];

   int low=0,high=0;

   int min=0;

   l=s.nextInt();

   p=s.nextInt();

   System.out.println("The values are "+l+"  "+p);

   table= new int[l+1][l+1];

   values= new ArrayList[l+1][l+1];

   al= new int[p];

   for(int i=0;i<p;i++)

   {

       al[i]=s.nextInt();

   }

   for(int i=0;i<=l;i++)

   for(int j=0;j<=l;j++)

       values[i][j]=new ArrayList<Integer>();

   System.out.println();

   for(int i=1;i<=l;i++)

       table[i][i]=0;

   //Arrays.s

   Arrays.sort(al);

   for(int i=0;i<p;i++)

   {

       System.out.print(al[i]+ "  ");

   }

   for(int len=2;len<=l;len++)

   {

       //System.out.println("The length is  "+len);

       for(int i=1,j=i+len-1;j<=l;i++,j++)

       {

           high= min_index(al,j-1);

           low= max_index(al,i);

           System.out.println("Indices are "+low+"  "+high);

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           {

           int cost=Integer.MAX_VALUE;;

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               if(temp!=cost)

               {

                   min=k;  

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                   //values[i][j].addAll(values[i][al[k]]);

                   //values[i][j].addAll(values[al[k]+1][j]);

                   //values[i][j].addAll(values[i][al[k]]);

               }

               //else

               //cost=0;

           }

           table[i][j]= len+cost;

           values[i][j].add(al[min]);

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   //temp=values[1][l];

   for(int e: values[1][l])

   {

       System.out.print(e+"-->");

   }

8 0
4 years ago
I have python homework and I’m struggling with it
melamori03 [73]

Answer:

okay

Explanation:

what's the question

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3 years ago
Exactly how many times must the merge function call each of read and write to merge two arrays of size n/2 into an array of size
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Answer:

Exactly how many times must the merge function call each of read and write to merge two arrays of size n/2 into an array of size n, assuming

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