True, because you get the same thing but it's only set up different.
Answer:
a) 0.80
b) 0.72
c) 0.02
Step-by-step explanation:
It is assumed that
X = Bit transmitted
Y = Bit received
= Transmissted bit is 0
= Transmissted bit is 1
= Received bit is 0
= Received bit is 1
As per the given condition
P [ | ] = 90%
P [ | ] = 100% - 90% = 10%
P [ | ] = 74%
P [ | ] = 100% - 74% = 26%
P [ Tramitted bits are 0 ] = 80%
Now calculate each situation
a)
As all the transmitted bits are o has possibilit of 80% then
P [ X = 0 ] = P [ ] = 80% = 0.80
b)
P [ X = 0, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 90% x 80% = 72% = 0.72
c)
P [ X = 1, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 10% x ( 100% - 80% ) = 10% x 20% = 2% = 0.02
Answer:
164 ft squared
Step-by-step explanation: