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Gre4nikov [31]
1 year ago
6

You are working for a catering company and have

Mathematics
2 answers:
Scrat [10]1 year ago
5 0

Answer:

0 to 125 bottles

Step-by-step explanation:

because you have $500 dollars, and you want to have $350 dollars [at least] left over, you can only spend $150 [500 - 350 = 150] dollars.

if we can spend up to $150 dollars, there is a large range of numbers of bottles that would meet the situation.

(multiplied by 1.20 because that is the price of 1 bottle. You are finding how many "1.20s" go into a certain number--150. )

If you buy 0 bottles, you will be spending

1.20 × 0 = 0

0 dollars

If you spend 30 bottles, you will be spending

1.20 × 30 = 36

36 dollars

So, how many bottles can we possibly buy?

To find this number, we can work backwards from our equation

(our equation is 1.20 × number of bottles)

I will be writing "number of bottles" as "x"

We know that 1.20 · x ≤ 150

(≤ means less than or equal to. we can spend <u>less than</u> 150 dollars, or we can spend 150 dollars exactly)

So, we can divide both sides of our equation by 1.20 to find the number of bottles [x] fit into 150.

  1.20  ·  x    ≤    150

÷1.20                   ÷1.20

            x   ≤    125

So, we can buy 0 to 125 bottles of water {to have at least 350 dollars left over}

garri49 [273]1 year ago
3 0

Step-by-step explanation:

500-350=150, you have 150 to buy bottles with

150÷1.20=125

you can buy 125 bottles with 350 left over

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   3. 43.96 cm

  4. 81.64 ft

Step-by-step explanation:

3. The formula for the circumference of a circle in terms of radius is ...

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The only answer choice even close to 6.28×(7 cm) is the one shown above.

___

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<em>Comment on the solution</em>

For questions like these, you only need to be able to estimate the answer to 1 or 2 significant digits. The answer choices are not so close together as to cause any confusion.

6×7 = 42, so the answer will be a few more than 42.

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What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

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