Answer:
63 degrees
Step-by-step explanation:
(180-54)/2=126/2=63
1/4(6 + 2c) > 3
0.25 (6+ 2c) > 3
1.5 + 0.5c > 3
0.5c > 1.5
c > 3
Or multiply both sides by 4 to get rid of the 1/4,
6 + 2c > 12
2c > 6
c >3
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
40
Step-by-step explanation:
3a + 2b =
3(10) + 2(5)
30 + 10 = 40
I hope this helps!
Have a great day!
original points (-2,0), (2,0), (0,2)
new points (-6.25,0),(6.25,0),(0,6.25)
the point (0,6.25) is the vertex that lies on y -axis