10 centimeters per second = 25.4 inches per second.

. The table shows the distance a truck

nirvana33 [79]

Answer:

see photo attached for detailed analysis.

5 0

2 years ago

Two groups of friends go to a movie. Each ticket costs the same amount. One group spends $57. The other group spends $95. List

kenny6666 [7]

Answer:

1) All possible number tickets for group that spends $57: A, B, C, D

2) All possible number tickets for group that spends $95: B, C, E, F

3) Each ticket will cost at most $19

Step-by-step explanation:

We are told that one group spends $57 dollars while the other group spends $95.

Now,we want to find all possible whole number ticket prices for each group and at most how much each ticket costs.

To do this, let's first find the factors of both amounts which will give us all possible whole number ticket prices for each group.

57: 1, 3, 19, 57

95: 1, 5, 19, 95

Since each ticket costs same amount, to find out at most how much each ticket costs, we will select the highest common factor of both groups which is 19.

Thus,each ticket will cost at most $19

8 0

3 years ago

A rectangle has a length 10 more than its width. If the width is increased by 8 and the length by 4, the resulting rectangle has

Aleks [24]

The Solution to the problem of the rectangle is given below

For Part A:

equation model: (14 + w) * (w +8) = 132
Length = 15

For Part B

Perimeter = 46

Meaning of Perimeter

The perimeter of any shape can be defined as the total sum of the sides of the shape.

<h3>Analysis</h3>

For Part A

equation model= (14 + w) * (w +8) = 135

14w + 112 + 8w + $w^{2}$ = 135

$w^{2}$ + 22w - 23 = 0

solving the quadratic equation

w = -23 or 1

Because we are dealing with a physical quantity we will make use of the value 1

lenght of original rectangle = 10 + 1 = 11

Part B

Perimeter= 2(length) * 2 (breadth) = 2(11 + 4) * 2 (1 + 8)

Perimeter = 48

In conclusion, The Solution to the problem of the rectangle is given above.

Learn more about Perimeter: brainly.com/question/19819849

#SPJ1

4 0

2 years ago

Read 2 more answers

I NEED ALOT OF HELP SOMEONE!

DedPeter [7]

V = 1/3 * 3.14 * 11 * 6^2 = 414.48 m^3

cost = V * 20 = 414.48 * 20 = 8289.60

4 0

3 years ago

Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w

ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between [1.5,1.75].

Step-by-step explanation:

We have $f(x)=3^x-x^4$

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

$f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)$

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

$f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13$

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

$f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)$

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

$f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5$

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

$f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13$

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

$f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)$

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

$f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)$

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0

3 years ago