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Alisiya [41]
3 years ago
15

Mr. Santiago can buy light fixtures in packages of 12 and light bulbs in packages of 9. He bought the fewest number of light fix

tures and light bulbs so that there is exactly one bulb per fixture with none left over.
How many packages of light fixtures and how many packages of light bulbs did Mr. Santiago buy?


Please Help
Mathematics
2 answers:
miskamm [114]3 years ago
5 0

List the multiples of both 12 and 9:

12, 24, 36, 48, 60

9, 18, 27, 36, 45

The lowest common multiple is 36.

This will make the fixtures and bulbs equal.

This means they bought 3 packages of light figures 3 x 12 = 36)

And bought 4 packages of bulbs ( 4 x 9 = 36)

Diano4ka-milaya [45]3 years ago
4 0

Find out LCM of 9,12

  • LCM=2(2)(3)(3)=36

Now

No of light packages=36/12=3

No of light bulbs=36/4=9

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Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he'll call her on the
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Answer:

The probability of Thomas inviting Madeline to the party over the phone is 0.143.

Step-by-step explanation:

Consider the tree diagram below.

The events are denoted as follows:

<em>A</em> = Thomas bumps into Madeline at school

<em>B</em> = Thomas call Madeline on the phone

<em>X</em> = Thomas asks Madeline to the party

The information provided is:

P (A) = 0.80

P (B) = 1 - P (A) = 1 - 0.80 = 0.20

P (X|A) = 0.90

⇒ P (X'|A) = 1 - P (X|A) = 1 - 0.90 = 0.10

P (X|B) = 0.60

⇒ P (X'|B) = 1 - P (X|B) = 1 - 0.60 = 0.40

The conditional probability of event <em>U</em> given that another events <em>V</em> has already occurred is:

P(U|V)=\frac{P(V|U)P(U)}{P(V)}

The law of total probability states that:

P(V)=P(V|U)P(U)+P(V|U')P(U')

In this case we need to determine the probability that Thomas invites Madeline to the party over the phone, i.e. P (B|X).

Use the law of total probability to determine the value of P (X) as follows:

P(X) = P(X|A)P(A)+P(X|B)P(B)

         =(0.90\times 0.80)+(0.60\times 0.20)\\=0.72+0.12\\=0.84

Compute the value of P (B|X) as follows:

P(B|X)=\frac{P(X|B)P(B)}{P(X)}

             =\farc{0.60\times 0.20}{0.84}\\\\=0.14286\\\\\approx 0.143

Thus, the probability of Thomas inviting Madeline to the party over the phone is 0.143.

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4 years ago
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