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notka56 [123]
3 years ago
12

456 000 has been rounded to the nearest thousand. What was the smallest possible number this could have been?

Mathematics
2 answers:
Reika [66]3 years ago
3 0
The smallest possible number could have been 455,500
Alexxandr [17]3 years ago
3 0

Answer:

The smallest possible number this could have been = 455500

Step-by-step explanation:

456000 has been rounded to the nearest thousand.

If the value is more than 456500 the value rounded to the nearest thousand is 457000.

If the value is less than 455500 the value rounded to the nearest thousand is 455000.

In between 455500 and 456500 the value rounded to the nearest thousand is 456000.

So,  The smallest possible number this could have been = 455500

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The answer is 43.967cm because circumference is equal to pi times the diameter, or two times pi times the radius.
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3 years ago
Lily swims for 5 hours in stream that has a current of 1 mph. She leaves her dock, swims upstream for 2 miles and then swim back
antiseptic1488 [7]

Answer:

Swimming speed in still water is approximately 1.5 mph

Step-by-step explanation:

Given the speed of the current = 1 mph

distance she swims upstream =2 miles,

the total time = 5 hours.

She swam 2 miles upstream against the  current and 2 miles back to the dock with  the current. The formula that relates  distance, time, and rate is d = r t\ \ \ \ or  \ \ \  t= \frac{d}{r}

Let x be the speed in still water.

Then  her speed with the current is x + 1, and

her speed against the current is x – 1.

Total time is equal to 2 miles with upstream and 2 miles downstream.

\frac{2}{x+1}+\frac{2}{x-1}=5\\\\\frac{2(x-1)}{(x+1)(x-1)}+\frac{2(x+1)}{(x-1)(x+1)}=5\\\\\frac{2x-2}{(x^2-1)}+\frac{2x+2)}{(x^2-1)}=5\\\\\frac{2x-2+2x+2)}{(x^2-1)}=5\\\\4x=5(x^2-1)\\4x= 5x^2-5\\0= 5x^2-4x-5

Now Using quadratic formula to solve above equation we get;

x= \frac{-b \±\sqrt{b^2-4ac}} {2a}\\\\here \ \ a= 5,b=-4,c=-5\\\\x= \frac{-(-4) \±\sqrt{(-4)^2-4\times 5\times-5}} {2\times5}\\\\x=\frac{4 \±\sqrt{16+100}} {10}\\\\x=\frac{4 \±\sqrt{116}} {10}=x=\frac{4 \±2\sqrt{29}} {10}= x=\frac{2 \±\sqrt{29}} {5}\\ x \approx 1.5 \ or \ x = -0.7

Since speed must be positive, Hence speed of still water is about 1.5 miles per hour.

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3 years ago
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3 years ago
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Answer:

Step-by-step explanation:

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8 0
3 years ago
A and B are partner in a business .A contribution RS 20000 and B rs 30000 a however acts as a manager the understanding being th
Vesna [10]

Answer:

Rs 1,650

Step-by-step explanation:

The given contribution are;

<em>A</em> contributes Rs 20,000, and <em>B</em> contributes Rs 30,000

The percentage of the profit <em>A</em> receives as manager = 25%

The amount of the profit divided in the ratio of their contribution = The remaining profit (75%)

The amount <em>B</em> gets = Rs1,350

The amount <em>A</em> gets = required

The ratio of their contribution at which the remaining profit is shared = 20,000:30,000 = 2:3

Where, out of 5 parts of 75% of the profits, <em>B</em> gets 3, while <em>A</em> gets 2

Let <em>P</em> represent the profit, we have;

B's share = 3/5× 0.75 × P = 1,350

∴ P = (5 × 1,350/3)/0.75 = 3,000

<em>A</em> gets 25% of the profits and 2/5 of the 75% remaining profit

∴ The amount <em>A</em> gets = 0.25×3000 + (2/5)×0.75×3000 = 1,650

Or simply put;

<em>A</em> gets the remainder of the profit which is Rs 3,000 - Rs 1,350 = Rs 1,650

8 0
2 years ago
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