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3 years ago

456 000 has been rounded to the nearest thousand. What was the smallest possible number this could have been?

Mathematics

2 answers:

Reika [66]3 years ago

3 0

The smallest possible number could have been 455,500

Alexxandr [17]3 years ago

3 0

Answer:

The smallest possible number this could have been = 455500

Step-by-step explanation:

456000 has been rounded to the nearest thousand.

If the value is more than 456500 the value rounded to the nearest thousand is 457000.

If the value is less than 455500 the value rounded to the nearest thousand is 455000.

In between 455500 and 456500 the value rounded to the nearest thousand is 456000.

So, The smallest possible number this could have been = 455500

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Write an equation in slope-intercept form for the graph shown. (1,0) (0,-2)

AlladinOne [14]

Answer:

y= 2x -2

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is they y-intercept

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$\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }$

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2 years ago

The local take out pizza place or 40 plain pizzas last week they sold 65% more plain pizzas this week than last week how many pl

Artemon [7]

Answer:

They sold a total of 66 pizzas.

Step-by-step explanation:

65% of 40 = 26

40 + 26 = 66 pizzas

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3 years ago

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Step-by-step explanation:

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3 years ago

Ralph sold brownies for $0.28 a piece in order to buy baseball cards. If the card cost $0.60 per pack, and if Ralph had no money

Svetradugi [14.3K]

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3 years ago

A teacher has brought treats for her 10 students. She will give out 3 fruit snacks, 2 teddy grahams, and 5 granola bars. How man

JulsSmile [24]

Answer:

2520 ways

Step-by-step explanation:

We can solve this problem with 3 combinations:

First the teacher needs to give 3 fruit snacks to 10 students, so we have a combination of 10 choose 3: C(10,3) = 10! / (3! * 7!) = 120

Then, she needs to give 2 teddy grahams to 7 students (3 already got a snack), so a combination of 7 choose 2: C(7,2) = 7! / (2! * 5!) = 21

The, she gives the 5 granola bars to the other 5 students, so a combination of 5 choose 5: C(5,5) = 1.

Now we just need to multiply the combinations to find the result:

C(10,3) * C(7,2) * C(5,5) = 120 * 21 * 1 = 2520 ways

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3 years ago