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Lorico [155]
2 years ago
15

Quadrilateral abcd has the vertices a(-6,4) , b(-4,5) , c(-3,3) , d(-5,1) . determine if quadrilateral abcd is a rhombus

Mathematics
1 answer:
bazaltina [42]2 years ago
3 0

Answer:

No

Step-by-step explanation:

The defining property of a rhombus is that it has equal side lengths.

=============================================================

Finding all side lengths :

<u>AB</u>

⇒ √(-4 + 6)² + (5 - 4)²

⇒ √2² + 1²

⇒ √5 units

<u>BC</u>

⇒ √(-3 + 4)² + (3 - 5)²

⇒ √1² + (-2)²

⇒ √5 units

<u>CD</u>

⇒ √(-5 + 3)² + (1 - 3)²

⇒ √(-2)² + (-2)²

⇒ √8 units

<u>DA</u>

⇒ √(-6 + 5)² + (4 - 1)²

⇒ √(-1)² + 3²

⇒ √10 units

As all side lengths of the quadrilateral are not equal, ABCD is not a rhombus.

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