All categories

3 years ago

Find the value of two numbers if their sum is 12 and their difference is 4

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

x + y = 12

Equation 2: Difference:

x - y = 4

Solution:

x + y = 12

x - y = 4

-------------

Add the two equations together:

2x = 16

Divide both sides by 2:

x = 8

Solve for y:

Use equation 1 substituting for x:

x + y = 12

8 + y = 12

Subtract 8 from both sides:

y = 4

Answer:

one number is 8 and the other number is 4.

8 + 4 = 12

8 - 4 = 4

<h2><u>Mark as Brainliest</u></h2>

You might be interested in

Nitrogen and oxygen are the most abundant gases in Earth’s atmosphere. A nitrogen molecule is 0.00000000003 meters larger than a

Verdich [7]

= 3 × 10-11
(scientific notation)

= 3e-11
(scientific e notation)

= 30 × 10-^12
(engineering notation)
(trillionth; prefix pico- (p))

= 0.0000000000
<span>(real number)</span>

4 0

3 years ago

Read 2 more answers

(1a) Do 4x and 15 + x have the same value when x is 5? How do you know?

diamong [38]

Answer:

Yes, both have the same value ( 20) when x = 5.

Step-by-step explanation:

We have two functions:

y = 15 + x

y = 4*x

We want to see if these functions have the same value when x = 5.

Then we just need to replace x by 5 in both equations, and see if the values of y are the same

first function:

y = 15 + 5 = 20

second function:

y = 4*5 = 20

So yes, both functions are equal to 20 when x = 5.

5 0

3 years ago

Read 2 more answers

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

Can someone help me solve this

Scrat [10]

Answer:

your photo dose not work

Step-by-step explanation:

but you would half to email it to me then i can help you if you want to do that

8 0

3 years ago

HELP ME ASAP!!!!!!!!

coldgirl [10]

Step-by-step explanation:

a. 6 £/hr

b. 6.8 £/hr.....is this right?

8 0

3 years ago

Read 2 more answers