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tino4ka555 [31]
3 years ago
7

What is -184.4 rounded to the nearest tenth place

Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer: I guess it would be -184.4, but it depends on what is after the last 4

Step-by-step explanation: all you gave was -184.4 but there needs to be at least 1 number after the last 4 in order to be able to round it

Deffense [45]3 years ago
4 0

Answer:

-184

Step-by-step explanation:

The 0.4 isn't 5 or greater so it won't be rounded up as 1.

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Answer:

1)Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

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4) p_v =2*P(z

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Step-by-step explanation:

Data given and notation

\bar X_{men}=23 represent the mean for the sample men

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\sigma_{men}=5 represent the population standard deviation for the sample men

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n_{men}=25 sample size for the group men

n_{women}=30 sample size for the group women

t would represent the statistic (variable of interest)

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1)Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

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Based on the significance level\alpha=0.01 and \alpha/2=0.005 we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40  

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∴ d = 2a

→ That means d is twice a or a is half d

∴ a : d = 1 : 2

The ratio of the first term to the common difference is 1 : 2

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