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puteri [66]
1 year ago
11

You pick a card at random.

Mathematics
1 answer:
katrin [286]1 year ago
7 0

Answer:

The probabily of P(not less than 6) is

P= the favorable outcomes/ the total outcomes

favorable out come is 1 case(7)

the total outcomes are 5 cases(2,3,5,6)

P=1/5=20%

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Which of the following best describes the nitrogen fixation process?(1 point) Consumers convert nitrogen gas into ammonia, nitri
nordsb [41]

Answer:

Soil bacteria convert nitrogen gas into ammonia, nitrites, and then nitrates. Nitrates are then absorbed by producers.

Step-by-step explanation:

.

7 0
2 years ago
Devon is 30 years older than his son, Milan. The sum of both their ages is 48. Using the variables d and m to represent the ages
statuscvo [17]

Answer+Step-by-step explanation:

m = man's age

s = son's age

m=s+36

(m+8)=3*(s+8)

Resolves to: s=10, m=46

So the man is 46 (=10+36).

In 8 years, son is 18 (=10+8), man is 54 (=3*18 and 46+8), thank you.

5 0
2 years ago
Solve: x^4-34x^2=-225
dangina [55]
X
4
−34x
2
+225=0

2 Factor
x
4
−
34
x
2
+
225
x
4
−34x
2
+225.
(
x
2
−
25
)
(
x
2
−
9
)
=
0
(x
2
−25)(x
2
−9)=0

3 Solve for
x
x.
x
=
±
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8 0
3 years ago
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
F(x) = -4x - 3<br> Evaluate f(9) + f(5)=
RSB [31]

Evaluate f(9) + f(5)= 14f If I didn't answer Your Question fully than tell me please!

7 0
3 years ago
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