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Radda [10]
3 years ago
8

2 angles of a triangle is 65 and 57 how to find the third angle

Mathematics
2 answers:
MArishka [77]3 years ago
7 0
Add 65+57 and subtract it from 180 then you get the third angle
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

Answer is 58

Step-by-step explanation:

65 + 57 = 122

180-122=58

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In triangle abc, the angle c is six times as large as angle
mote1985 [20]
The interior angles of a triangle add up to 180 degrees

a = 1st angle, b = 2nd angle, c = 3rd angle

c = 6a
b = a + 60
a + b + c = 180

a + (a + 60) + (6a) = 180
8a + 60 = 180
8a = 180 - 60
8a = 120
a = 120/8
a = 15 <=== here is one angle

b = a + 60
b = 15 + 60
b = 75 <=== and another one

c = 6a
c = 6(15)
c = 90 <=== and the last angle

3 0
3 years ago
Simplify: −z^3+5k^6−(−z^3+10k^6)
Georgia [21]
-z³ + 5k^6 + z³ -10k^6

(-z³ cancels out with z³)

5k^6 -10k^6

(then subtract)

Answer is -5k^6
6 0
4 years ago
It takes 68 days for John to plants to grow 3 centimeters. About how many weeks is that? The answers choices are as follow : abo
Nesterboy [21]
We know that there are 7 days in a week, so just divide 68 ÷ 7 and you should get 9.71 which is approximately 10 weeks
5 0
4 years ago
Read 2 more answers
The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is
svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2

The degree of polynomial p (x) is:

\text{deg}\ p (x)=6

The degree of polynomial q (x) is:

\text{deg}\ q (x)=5

The difference of the degrees of the polynomials p (x) and q (x) is:

\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0
4 years ago
F(n)=45⋅(4/5)^n−1<br> complete the recursive formula of f(n)
Radda [10]

F(1) = 45

f(n) = f(n-1) * 4/5

Step-by-step explanation:

f(n) = 45 x (4/5)ⁿ⁻¹

f(1) = 45 x (4/5)¹⁻¹ = 45 x (4/5)⁰ = 45 x 1 = 45

f (n-1) = 45 x (4/5)ⁿ⁻¹⁻¹ = 45 x (4/5)ⁿ⁻²

f(n) = f(n-1) * (4/5)¹ = 45 x (4/5) ⁿ⁻²⁺¹ = 45 x (4/5)ⁿ⁻¹

7 0
3 years ago
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