Answer:
It is b
Step-by-step explanation:
Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
--------------
The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
----------
That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
20/3 ounces of water is added.
9514 1404 393
Answer:
103°
Step-by-step explanation:
The law of sines tells you ...
sin(C)/c = sin(A)/a
sin(C) = (c/a)sin(A)
C = arcsin(c/a·sin(A)) = arcsin(37/19·sin(30°)) ≈ 180° -76.8° ≈ 103°
Obtuse angle C is about 103°.
First, you solve the exponent: 2(8-4)
—————
32
Do PEMDAS
2(4)
——
32
8
—
32
1
—
4
That’s your final answer :)
I think that the answers is b
