Answer:
2, 5, 14, 41, 122
Step-by-step explanation:
Using the recursive rule with a₁ = 2
a₂ = 3a₁ - 1 = 3(2) - 1 = 6 - 1 = 5
a₃ = 3a₂ - 1 = 3(5) - 1 = 15 - 1 = 14
a₄ = 3a₃ - 1 = 3(14) - 1 = 42 - 1 = 41
a₅ = 3a₄ - 1 = 3(41) - 1 = 123 - 1 = 122
The first 5 terms are 2, 5, 14, 41, 122
Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
I'm guessing the question is meant to be "<span>If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.
Area of a circle =</span>πr^2
5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2
The area of the postal box base is 231.04 cm^2.
