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2 years ago

Find the greatest common factor of 6m² and 7m².

Mathematics

1 answer:

77julia77 [94]2 years ago

8 0

Answer:

your answer is 4 my friend

Step-by-step explanation:

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Peri spent 40% of her money on books and 50% of the rest on toys. She has $21. How much money did she have first.

Vlad1618 [11]

40/100 + 50/100 = 90/100

il lui reste 10/100 ou 21 $

10 % = 21 $
100 % = 210 $

6 0

3 years ago

Eric drew a scale drawing of a country park. The scale he used was 1 inch = 2.5 yards. The picnic area is 80 yards wide in real

Alchen [17]

If 1 inch = 2.5 yards then
x inch = 80 yards
cross multiplying we have:
80 × 1 = x × 2.5
x = 80÷ 2.5 = 32 inches
therefore the picnic area is 32 inches in the drawing.

5 0

3 years ago

Let u=<-5,1>, v=<7,-4> find 9u-6v

katrin2010 [14]

9u -6v = 9<-5, 1> -6<7, -4>
.. = <9*-5 -6*7, 9*1 -6*-4>
.. = <-87, 33>

8 0

2 years ago

Read 2 more answers

Given the number 2464829438 what is the next number?

malfutka [58]

2464829438
The next number is 2,464,829,439

5 0

2 years ago

Read 2 more answers

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .

4 0

2 years ago