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Elza [17]
3 years ago
15

Which number line shows the solution set for |8 - 2p| = 6

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer:

I think b

Step-by-step explanation:

scoundrel [369]3 years ago
4 0

Answer:

<em>B) Number Line 2</em>

Step-by-step explanation:

I jus kno.

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Hey guys I need help plz asap
Ilya [14]
Answer:

Explanation:

AB = BC
=> Triangle ABC is an Isosceles Triangle
Thus, Angle C = Angle A
DE = BE
=> Triangle DEB is an Isosceles Triangle
Thus, Angle D = Angle B

Proof that triangle ABC and DEB are similar:

Angle DBE = Angle A (corresponding angle)
Angle BDE = Angle C (Both Triangle are Isosceles, if one pair of the angle are equal then the other pair should also be equal)

=> Triangle ABC ~ Triangle DEB (AA)

Therefore, Angle E = Angle B

Find angle B:

Angle C + Angle A + Angle B = 180
40 + 40 + angle B = 180
Angle B = 180 - 80
Angle B = 100 degree

But Angle B = Angle E = 100 degree

Therefore, Angle E = 100 degree
3 0
3 years ago
the outdoor temperaturedeclines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?
hodyreva [135]
15 degrees will be declined in the 5 hours.
3 0
3 years ago
Who wants to do an algebra 1 assignment for me? I will email you the pdf
andrew11 [14]

Answer:

No

Step-by-step explanation:

People arent on brainly to do others work, they are here to help, NOT DO YOUR WORK

Resepect us more please. We stay on here just to help people. We take time out of our days to help people. So please dont make them do your work. They are here to help not be your personal servant.

Have a wonderful day! :)

4 0
3 years ago
Read 2 more answers
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Find the value of x. Round to the nearest tenth.
lubasha [3.4K]

Answer:

x=400 m is the correct answer

5 0
3 years ago
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