We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

but this would imply that

, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

and solving gives

, which makes more sense. Then the number of extra spades in the deck must be 2.
Answer:
its b .
Step-by-step explanation:
Answer: =86
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* Hopefully the picture helps:) Mark me the brainliest:)
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Answer:
Step-by-step explanation:
Answer is 7/3