Answer:
x=2
Step-by-step explanation:
this is just like the last one. since it is vertical it only includes the x value 2
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Functions
- Function Notation
<u>Algebra II</u>
- Piecewise Functions<u>
</u>
<u>Calculus</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Continuous at x = 2

<u>Step 2: Solve for </u><em><u>k</u></em>
- Definition of Continuity:

- Evaluate limits:

- Evaluate exponents:

- Multiply:

- [Subtraction Property of Equality] Subtract 2 on both sides:

- Rewrite:

Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Limits - Continuity
Book: College Calculus 10e
Answer:jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
Step-by-step explanation:
Answer:
The z-score when x=187 is 2.41. The mean is 187. This z-score tells you that x = 187 is 2.41 standard deviations above the mean.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

The z-score when x=187 is ...

The z-score when x=187 is 2.41. The mean is 187. This z-score tells you that x = 187 is 2.41 standard deviations above the mean.
Answer:
see explanation
Step-by-step explanation:
c = a - 2b
= < 4, 5, 6 > - 2 < 1, 2, 3 > ← multiply each component by 2
= < 4, 5, 6 > - < 2, 4, 6 > ← subtract corresponding components
= < 4 - 2, 5 - 4, 6 - 6 > = < 2, 1, 0 >
| c | =
=
= 
-------------------------------------------------------------------------------------------------
sum the product of corresponding components
u.v = (3 × 2) + (- 2 × - 1) + (4 × - 6) = 6 + 2 - 24 = - 16