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mojhsa [17]
2 years ago
15

Write a C++ program to get the following output. 1 12 123 1234 12345​

Engineering
1 answer:
Nikolay [14]2 years ago
8 0

#include"stdafx.h"

#include<iostream>

usingnamespace std;

int main()

{

for(int i=1; i<=5; i++)

{

for(int j=1; j<=i; j++)

{

cout<<j ;

}

cout<<endl;

}

system("pause");

return  0;

}

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A) Gravity attracts horizontally downwards the weight of any object such a building or a part of building. (True / False)
PtichkaEL [24]

Answer:

  1. True
  2. True
  3. False
  4. True

Explanation:

  • True
  • True
  • False
  • True

3 0
3 years ago
The ________ is considered the normal operating control of an air conditioner, according to the Standards of Practice. thermosta
mamaluj [8]

Answer:

Thermostat

Explanation:

The thermostat is considered the normal operating control of an air conditioner, according to the Standards of Practice.

8 0
2 years ago
The "Crawler" developed to transport the Saturn V launch vehicle from the assembly building to the launch pad is the largest lan
Illusion [34]

Answer:

a) 152000 slugs

b) 2220000 kg or 2220 metric tons

Explanation:

A body with a weight of 4.9*10^6 lbf has a mass of

4.9*10^6 lbm * 1 lbf/lbm = 4.9*10^6 lbm

This mass value can then be converted to other mass values.

1 slug is 32.17 lbm

Therefore:

4.9*10^6 lbm * 1 slug / (32.17 lbm) = 152000 slugs

1 lb is 0.453 kg

Therefore:

4.9*10^6 lbm / (1/0.453) * kg/lbm = 2220000 kg

5 0
3 years ago
1. AC is safer for welders to use in hazardous spaces because currents are even, generate less spatter residue, and
igor_vitrenko [27]
Yes that’s correct . It’s safer cause of the current are even
6 0
3 years ago
A trapezoidal section has a 5.0-ft bed width, 2.5-ft depth, and 1:1 side slope. Evaluate its geometric elements (Area, water dep
aleksley [76]

Answer:

a) 18.75 ft^2

b) 2.5 ft

c) 12.07 ft

d) 10 ft

e) 1.553 ft

f) 1.875 ft

Explanation:

Given data :

5.0-ft bed width, ( b )

2.5-ft depth ( y )

1 : 1 side slope

Evaluate

a) Area of trapezoidal section

A = by + my^2

we assume m = 1

A = [5 + (1 * 2.5 ) ] *2.5

   = ( 7.5 ) 2.5  = 18.75 ft^2

b) Calculate water depth

water depth = 2.5 ft

c) Calculate wetted perimeter

P = b + 2y √ 1 + m^2

  = 5 + (2.5*2) √ 1 + 1 ^2  =   12.07 ft

d) calculate top width

    T = b + 2my

       = 5 + 2 ( 1 * 2.5 ) = 10 ft

e) calculate hydraulic radius

R = A / P = 18.75 / 12.07

               = 1.553 ft

f) calculate hydraulic depth

 D = A / T = 18.75 / 10 = 1.875 ft

4 0
3 years ago
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