Answer:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of 
then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Step-by-step explanation:
Information given
n=200 represent the random sample taken
X=75 represent the number of people Liberal
estimated proportion of people liberal
is the value that we want to test
z would represent the statistic
represent the p value
Hypothesis to test
We want to verify if the true proportion of adults liberal is higher than 0.24:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Answer:
B.21.3 is the correct answer
Step-by-step explanation:
1/2*x+1/4*x=16
x/2+x/4=16
2x+x/4=16
3x/4=16
3x=16*4
3x=64
x=21.3
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Let x = the amount of grapes that can be bought for 0.40.
Note: By 90 I assume you mean 90 cents. The same for 40.
12/x = 0.90/0.40
0.90x = 12(0.40)
0.90x = 4.80
x = 4.80 ÷ 0.90
x = 5.33333
We can round the decimal to the ones place to get 5 grapes.
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
<h3>What is the numerical value of DE?</h3>
Given the data in the question;
- E is a point between point D and F.
- Segment DF = 78
- Segment DE = 5x - 9
- Segment EF = 2x + 10
- Numerical value of DE = ?
Since E is a point between point D and F.
Segment DF = Segment DE + Segment EF
78 = 5x - 9 + 2x + 10
78 = 7x + 1
7x = 78 - 1
7x = 77
x = 77/7
x = 11
Hence,
Segment DE = 5x - 9
Segment DE = 5(11) - 9
Segment DE = 55 - 9
Segment DE = 46
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
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This problem can be solved from first principles, case by case. However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.
Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected
Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}
Therefore the
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}
