Answer:
Answer will be 50
Step-by-step explanation:
Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.
Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,
Five years ago,
Nuri’s age = x-5 years
Sonu’s age = y-5 years
And relation between ages can be given as
Nuri’s age = 3×sonu’s age or
x-5 = 3(y-5)
x-5 = 3y-15
x-3y+10 = 0 ………..(i)
Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.
So, ten years ago,
Nuri’s Age = x+10
Sonu’s Age = y+10
And relation between ages can be written as
x+10 = 2(y+10)
x+10 = 2y+20
x-2y-10 = 0 …………..(ii)
Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.
Value of ‘x’ from equation (i) be
x = 3y-10 ……….(iii)
Putting value of ‘x’ from equation (iii) in equation (ii) we get,
3y-10-2y-10 = 0
y = 20
Now, from equation (iii) value of ’x’ can be given as,
x= 3(20)-10
x = 50
Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.
*5 because the radius is half of the diameter.