F(x) = log10 (x) + 5
1 answer:
Answer:
Find the asymptotes.
Set the argument of the logarithm equal to zero.
x+5=0 . Subtract 5
from both sides of the equation. x=−5
The vertical asymptote occurs at x=−5
Vertical Asymptote: x=−5
<em>Find the point at x=−4</em>
Replace the variable x with −4
in the expression.
f(−4)=log((−4)+5)
Simplify the result. Add −4 and 5
f(−4)=log(1) Logarithm base 10 of 1 is 0
f(−4)=0
The final answer is 0
Convert 0 to decimal. y=0
<em>Find the point at x=5. </em>Replace the variable x with 5
in the expression.
f(5)=log((5)+5)
Simplify the result. Convert 1 to decimal. y=1
<em>Find the point at x=−3</em>
Replace the variable x with −3
in the expression.
f(−3)=log((−3)+5)
Simplify the result.
log(2) . Convert log(2) to decimal. y=0.30102999
The log function can be graphed using the vertical asymptote at x=−5 and the points (−4,0),(5,1),(−3,0.30102999)
Vertical Asymptote: x=−5
x y
−4 0
−3 0.301
5 1
Step-by-step explanation:
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<h2>The circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.</h2>
Step-by-step explanation:
Given,
The diameter of small pizza = 8 inches,
The diameter of medium pizza = 10 inches and
The diameter of large pizza (d) = 11 inches
To find, the circumference of each size of pizza = ?
We know that,
The circumference of the circle =
∴ The circumference of small size of pizza = 3.14 × 8 = 25.12 inches
The circumference of medium size of pizza = 3.14 × 10 = 31.4 inches
Also,
The circumference of large size of pizza = 3.14 × 12 = 37.68 inches
Thus, the circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.
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