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lyudmila [28]
2 years ago
8

a1" title="2\sqrt{27} + \sqrt{12} -3\sqrt{3} -2\sqrt{12}" alt="2\sqrt{27} + \sqrt{12} -3\sqrt{3} -2\sqrt{12}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
givi [52]2 years ago
7 0

2\sqrt{27} +\sqrt{12} -3\sqrt{3} -2 \sqrt{12}\\\\=2\sqrt{27}-3\sqrt 3-\sqrt{12}\\\\=2\sqrt{9 \times 3} - 3 \sqrt 3 - \sqrt{4 \times 3}\\\\=2\cdot 3\sqrt 3 -3 \sqrt 3 -2\sqrt 3\\\\=6\sqrt 3 -3\sqrt 3 -2\sqrt 3 \\\\=6\sqrt 3 - 5 \sqrt 3\\\\=\sqrt 3

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Please help i really need help i beg you it's only one question
Brums [2.3K]
If you don't have the T there is 19.5 for (-6,5) (-1,-2) Which would be 19.5. 

But if you needed the T the answer should be 19,5 Teslas.
5 0
4 years ago
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Death valley is one of the hottest places on earth with a recorded maximum temperature of 57°C the lowest temperature ever recor
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Answer:

The answer to your question is: ΔT = 146°C

Step-by-step explanation:

Data

Maximum temperature = 57°C

Lowest temperature = -89°C

ΔT = hottest temp - lowest temp

ΔT = 57 - (-89)

ΔT = 57 + 89

ΔT = 146°C

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3 years ago
Mahni plans to spend the next 12 weeks saving some of her income. She will save $x a week for the first 6 weeks and then $(2x −
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$x=213$

For first six weeks she saved 213$

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\\ \sf\longmapsto 2x-30=2(213)-30=426-30=396\$

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3 years ago
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6 0
4 years ago
C is the center of the circle. Find the area of the segment shown in the figure,
Semmy [17]

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: \theta= 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = \dfrac{\theta}{360^{\circ}}\times\pi r^2

Using above formulas in (i) and substituting corresponding values , we get

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Hence, the correct answer is A 28.50 sq. u

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4 years ago
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