Answer:
x=3.414 and x=0.59 is the desired answer.
Step-by-step explanation:
We are given a quadratic equation as :
on dividing both side by 2 we have the equation as
on solving for the roots of the equation using the quadratic formula we get that
and
x=2+1.414 and x=2-1.414
Hence , x=3.414 and x=0.586≈0.59.
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
